问题描述 无序数组求第K大的数,其中K从1开始算. 例如:[0,3,1,8,5,2]这个数组,第2大的数是5 OJ可参考:LeetCode_0215_KthLargestElementInAnArray 堆解法 设置一个小根堆,先把前K个数放入小根堆,对于这前K个数来说,堆顶元素一定是第K大的数,接下来的元素继续入堆,但是每入一个就弹出一个,最后,堆顶元素就是整个数组的第K大元素.代码如下: public static int findKthLargest3(int[] nums, int k)
思路: 利用快速排序的划分思想 可以找出前k大数,然后不断划分 直到找到第K大元素 代码: #include <iostream> #include <algorithm> #include <cstdio> using namespace std; int findK(int left, int right, int arr[], int k) { if(left >= right) return arr[left]; int first = left, las
传送门 The k-th Largest Group Time Limit: 2000MS Memory Limit: 131072K Total Submissions: 8690 Accepted: 2847 Description Newman likes playing with cats. He possesses lots of cats in his home. Because the number of cats is really huge, Newman wants
题目原文 Selection in two sorted arrays. Given two sorted arrays a[] and b[], of sizes n1 and n2, respectively, design an algorithm to find the kth largest key. The order of growth of the worst case running time of your algorithm should be logn, where n
转自 http://blog.csdn.net/zxzxy1988/article/details/8587244 给定两个已经排序好的数组(可能为空),找到两者所有元素中第k大的元素.另外一种更加具体的形式是,找到所有元素的中位数.本篇文章我们只讨论更加一般性的问题:如何找到两个数组中第k大的元素?不过,测试是用的两个数组的中位数的题目,Leetcode第4题 Median of Two Sorted Arrays方案1:假设两个数组总共有n个元素,那么显然我们有用O(n)时间和O(n)空间的
import java.util.Arrays; /* 核心思想:利用快排思想,先假定从大到小排序,找枢纽,枢纽会把大小分开它的两边,当枢纽下标等于k时, 即分了k位在它左边或右边,也就是最大或最小的排到了它的左边或右边了.那么那个枢纽就是要找的第k位了 */ public class SearchNumData { /* n为数组长度 k为要查找的第k大 */ public static int findKth(int[] a, int n, int K) { return findKth(a
Design a class to find the kth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element. Your KthLargest class will have a constructor which accepts an integer k and an integer array nums,
