We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c
如下代码段是关于C#返回字符串的字节长度,一个中文算两个字符的代码. public static int GetLength(string str) { if (str.Length == 0) return 0; ASCIIEncoding ascii = new ASCIIEncoding(); int tempLen = 0; byte[] s = ascii.GetBytes(str); for (int i = 0; i < s.Length; i++) { if ((int)s[i]
Given a string s , find the length of the longest substring t that contains at most 2 distinct characters. Example 1: Input: "eceba" Output: 3 Explanation: t is "ece" which its length is 3. Example 2: Input: "ccaabbb" Output
方法一:使用正则表达式,代码如下: function getByteLen(val) { var len = 0; for (var i = 0; i < val.length; i++) { var a = val.charAt(i); if (a.match(/[^\x00-\xff]/ig) != null) { len += 2; } else { len += 1; } } return len; } 方法二:使用字符unicode判断:方法如下: function getByteLe
项目中遇到客户的需求变化,要验证某个数据的正确性,判断输入的两位字符,第一位是数字16进制的,第二位是I.O.Q.U除外的字母(A到Z). 本来对js不熟练,网上参考了一下js正则验证的规则,使用正则表达式完成了这个验证. function check() { var str = document.getElementById("txtEnglishName").value; var reg=/^[0-9a-fA-F][^IOQU]$/; if (str.length!=2) { my