本内容是LeetCode第三道题目:无重复字符的最大子串 # -*- coding: utf-8 -*- """ Created on Sun Mar 10 20:14:53 2019 @author: Administrator Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb"
题目:给定一个字符串string,找出string中无重复字符的最长子串. 举例: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of 1. Given "pwwkew", the answer is "wke"
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
题目 最长无重复字符的子串给定一个字符串,请找出其中无重复字符的最长子字符串. 例如,在"abcabcbb"中,其无重复字符的最长子字符串是"abc",其长度为 3. 对于,"bbbbb",其无重复字符的最长子字符串为"b",长度为1. 解题 利用HashMap,map中不存在就一直加入,存在的时候,找到相同字符的位置,情况map,更改下标 public class Solution { /** * @param s: a s
Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of 1.
Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana
