Bad Hair Day Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 24420 Accepted: 8292 Description Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants
原文:http://www.cnblogs.com/AndyJee/p/4483043.html There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy
不容易系列之(4)——考新郎 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 37629 Accepted Submission(s): 13786 Problem Description 国庆期间,省城HZ刚刚举行了一场盛大的集体婚礼,为了使婚礼进行的丰富一些,司仪临时想出了有一个有意思的节目,叫做"考新郎",具体的操作
约瑟夫环问题. package pack; import java.util.*; public class demo_2 { static int a[]; public static void main(String[] args) { Scanner in=new Scanner(System.in); System.out.print("现在有M个小朋友,请输入M的值:"); int m=in.nextInt(); int a[]=new int[m+1]; for(int i
题目描述 Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer John has
题目链接 题解: 这个题可以用广搜来解决,从农夫到牛的走法每次都有三种选择,定义一个队列,把农夫的节点加进队列,然后以这三种走法找牛,队列先进先出,按顺序直到找到牛的位置. 代码: #include<iostream> #include<stdio.h> #include<queue> #include<cstring> using namespace std; int n,k; #define MAX 1e5 const int MAX_N=1e5+5;
