tic; % this method is transform from Ritz method %is used for solving two point BVP %this code was writen by HU.D.dong in February 11th 2017 %MATLAB 7.0 clear clc N=50; h=1/N; X=0:h:1; f=inline('pi^2/2*sin(pi/2*x)'); %以下是右端向量: for i=2:N fun1=@(x) f(X
tic; % this method is transform from Galerkin method %also call it as finit method %is used for solving two point BVP which is the first and second term. %this code was writen by HU.D.dong in February 11th 2017 %MATLAB 7.0 clear; clc; N=50; h=1/N; X=
v$parameter视图中查询参数的时候其实都是通过x$ksppi和x$ksppcv这两个内部视图中得到的. 1. 可以通过如下方式查询当前实例的所有隐含参数: col name for a30;col value for a10;selectx.ksppinm name,y.ksppstvl value,y.ksppstdf isdefault,decode(bitand(y.ksppstvf,7),1,'MODIFIED',4,'SYSTEM_MOD','FALSE') ism
Max Factor Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 10245 Accepted Submission(s): 3304 Problem Description To improve the organization of his farm, Farmer John labels each of his N (1
题意大概是: 一个数比如242,把所有数字分成两组,而且两组的和相等,那么这个数就是神奇数,此时242,能够分成{2,2}和{4},所以242是神奇数. 题目要求输入n和m求[n,m]区间内神奇数的个数. 思路: 对于任意一个数字,将每一位上的数字保存到数组里,并求所有位上的数字的和sum.然后使用回溯法遍历数组, 查看数组内是否存在和为sum/2的情况,如果存在则为神奇数. bool isfind(vector<int>& nums, int sum, int cur, int be