package b; public class Rect { Double width; Double height; public Double getWidth() { return width; } public void setWidth(Double width) { this.width = width; } public Double getHeight() { return height; } public void setHeight(Double height) { this
// 图形类Shape package d922B; public class Shape { double getArea(ShapePara x){ return x.getArea(); } double getArea(Rect y) { return y.getA()*y.getB(); } } //矩形类 package d922B; public class Rect extends Shape { private double a, b; public Rect(double a
Find the total area covered by two rectilinear rectangles in a2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. Cre
Find the total area covered by two rectilinearrectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Example: Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2 Output:
条款32:确定你的public继承塑模出is-a关系 以public继承的类,其父类的所有的性质都应该使用与子类,任何需要父类的地方都应该能用子类来代替,任何子类类型的对象也同时是父类的: class Person{...}; class Student : public Person{...}; void eat(const Person& p); void study(const Student& s); Person p; Student s; eat(p); eat(s); stu
A. Window B. Paper Game Des:给你一个矩形集合,一开始只有一个W*H的矩形.每次可以选一个矩形,切成两个并加入集合,长和宽必须是正整数.不能操作者输,求先手赢还是输.(1 ≤ W,H ≤ 100,000). Sol: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; int i, j,
