假设一组数据:人员进出刷卡数据表[SwingCard] ID MenID Door 1 1 In 2 1 In 3 1 Out 4 1 In 5 1 Out 6 1 Out 想要变成如下:一进一出为一组横着排放,缺少数据的补null MenID Door1 Door2 1 In null 1 In Out 1 In Out 1 null Out 实现: --重新排序,序号为浮点型,装入临时表#Copy select MenID,Door,Row=(Row_Number() over(order
总结::需要耐心,加思考.做事不思考,那就是白做徒劳!!!!! package com.aini; import java.util.Scanner; //操...为什么数组的大小比较我硬是搞不懂,比较大小依然放在for循环里... //从键盘输入一组数据,并输出最小值 //还有循环结构的括号不知道在哪里结束 public class erte { public static void main(String[] args) { Scanner c = new Scanner(System.in
SELECT * FROM rsl a, (SELECT CODE, max(time_key) time_key FROM rsl GROUP BY CODE ) b WHERE a. CODE = b. CODE AND a.time_key = b.time_key AND a. CODE IN ('HK.00700', 'HK.03888'); table :rsl 然后查询出根据每一种的code 中最新的一组数据