SQL SERVER 查询第20行到30之间的数据 1.先查询前20行的ID,后查询除去20条记录的前10条记录 SELECT TOP 10 * FROM tbBank WHERE BankID NOT IN(SELECT TOP 20 BankID FROM tbBank ORDER BY BankID ASC) 2.先查询前20行记录最大的ID,后查询大于该值的前10条记录 SELECT TOP 10 * FROM tbBank WHERE BankID>(SELECT MAX(BankID
时间:2017-09-11 整理:byzqy 题目:用一条SQL语句查询出每门课都大于80分的学生姓名. 最近面试C#开发工程师,碰到上面这个考数据库的题目,自己感觉有点难度,没有思路,现将找到的解决方案整理如下: 文件:SQLQuery1.sql /* 环境:Microsoft SQL Server 2012 工具: Microsoft SQL Server Management Studio 数据库: Interview 数据表: grade 详情: name class score 张三
1.先查询前20行的ID,后查询除去20条记录的前10条记录 SELECT TOP * FROM tbBank WHERE BankID NOT IN(SELECT TOP BankID FROM tbBank ORDER BY BankID ASC) 2.先查询前20行记录最大的ID,后查询大于该值的前10条记录 SELECT TOP * FROM tbBank WHERE BankID>(SELECT MAX(BankID) FROM (SELECT TOP BankID FROM tbBa
Course表如下: 查询出每门课都大于80 分的学生姓名有两种方法. 1.select distinct name from Course where name not in (select distinct name from Course where score<=80) 2.select name from Course group by name having min(score)>80
select sname from student where not exists (select * from course where not exists (select * from sc where sno =student.sno and cno=course.cno); 最内部的 select * from sc where sno=student.sno and cno = course.cno是查询出所有已经选择过课程的学生及相应课程,select * from cour
此情况用于数据库中没有“年龄”这个字段,只有“出生日期”这个字段.先计算出“年龄”,在分组查询. 1.SELECT *, ROUND(DATEDIFF(CURDATE(), popBirthday)/365.2422) AS '年龄' FROM population :这是获取当前日期, 在根据“出生日期”,计算出“年龄”,AS 后面取的“年龄的别名”,数据库里并没有“年龄”这个字段. 2. Select popSex,popNative, Sum(Case When 年龄 <=20 Th
select case left(idcard,2) when '11' then '北京市'when '12' then '天津市'when '13' then '河北省'when '14' then '山西省'when '15' then '内蒙古自治区'when '21' then '辽宁省'when '22' then '吉林省'when '23' then '黑龙江省'when '31' then '上海市'when '32' then '江苏省'when '33' then '浙江
elect case left(idcard,2) when '11' then '北京市' when '12' then '天津市' when '13' then '河北省' when '14' then '山西省' when '15' then '内蒙古自治区' when '21' then '辽宁省' when '22' then '吉林省' when '23' then '黑龙江省' when '31' then '上海市' when '32' then '江苏省' when '33
SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO -- ============================================= -- Author: wgx -- Create date: <Create Date, ,> -- Description: <Description, ,> -- ============================================= CREATE FUNCTION
function ages(str) { var r = str.match(/^(\d{1,4})(-|\/)(\d{1,2})\2(\d{1,2})$/); if(r==null)return false; var d= new Date(r[1], r[3]-1, r[4]); if (d.getFullYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()==r[4]) { var Y = new Date().getFu