package java1; public class People { public String name; public int age; public String sex; public String height; People(String name, int age, String sex, String height) { this.name = name; this.age = age; this.sex = sex; this.height = height; } publ
package com.chuoji; public class People { private String name; private int age; private String sex; private double height; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return ag
18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23314 Accepted Submission(s): 7461 Problem Description Gardon的18岁生日就要到了,他当然很开心,可是他突然想到一个问题,是不是每个人从出生开始,到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,所以他
18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16784 Accepted Submission(s): 5317 Problem Description Gardon的18岁生日就要到了,他当然很开心,可是他突然想到一个问题,是不是每个人从出生开始,到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,所以他
18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23411 Accepted Submission(s): 7494 Problem Description Gardon的18岁生日就要到了,他当然非常开心,但是他突然想到一个问题,是不是每一个人从出生開始.到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,
SELECT *, Age= datediff(yy,cast(case when substring(PersonalId,,) ') /*若第7位不是'1'或'2'则表示是15位身份证编码规则*/ then substring(PersonalId,,) ,) end as datetime),getdate()) FROM Student WHERE datediff(yy,cast(case when substring(PersonalId,,) ') then substring(P
此情况用于数据库中没有“年龄”这个字段,只有“出生日期”这个字段.先计算出“年龄”,在分组查询. 1.SELECT *, ROUND(DATEDIFF(CURDATE(), popBirthday)/365.2422) AS '年龄' FROM population :这是获取当前日期, 在根据“出生日期”,计算出“年龄”,AS 后面取的“年龄的别名”,数据库里并没有“年龄”这个字段. 2. Select popSex,popNative, Sum(Case When 年龄 <=20 Th