----------用来双重排序,且获取唯一 go SELECT ROW_NUMBER() OVER (ORDER BY AScore DESC,ATime ASC) AS Rank, * FROM ( SELECT AScore,ATime,MerchantWeixinUserID, ROW_NUMBER() OVER (partition by MerchantWeixinUserID order by ASCORE DESC,ATime ASC) AS SX FROM ( ),Create
oracle查询:取出每组中的第一条记录按type字段分组,code排序,取出每组中的第一条记录 方法一: select type,min(code) from group_info group by type; 注意:select 后面的列要在group by 子句中,或是用聚合函数包含,否则会有语法错误. 方法二: SELECT * FROM(SELECT z.type , z.code ,ROW_NUMBER()OVER(PARTITION BY z.type ORDER BY z.cod
比如上图,取3,4行记录的第一行也就是3行,而不返回4行. 使用分析函数row_number() over (partiion by ... order by ...)来进行分组编号,然后取分组标号值为1的记录即可.目前主流的数据库都有支持分析函数,很好用,比如使用下面的方式. select s.* from ( select *, row_number() over (partition by [手机号] order by [店铺]) as group_idx from table_name
SELECT * FROM EnterpriseDataTools.Enterprise.CompanyMainwhere CompanyNo in (select CompanyNo from EnterpriseDataTools.Enterprise.CompanyMain group by CompanyNo having count(CompanyNo) > 1)and Id not in (select max(Id) from EnterpriseDataTools.Enterpr
CREATE TABLE [TestTable] ( ) NOT NULL , ) NOT NULL , ) ))) GO ALTER TABLE [TestTable] ADD PRIMARY KEY ([uid], [key]) GO ) GO ) GO ) GO ) GO ) GO ) GO WITH cte AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY uid ORDER BY [key] DESC) AS rn FROM vtable )
Oracle 查询出来的数据取第一条 --------------------------------------------------------------------------- 转载自:http://www.itpub.net/thread-246442-1-1.html select * from (select * from <table> order by <key>) where rownum=1; select * from (select * from &l
一.背景 一张person表,有id和name的两个字段,id是唯一的不允许重复,id相同则认为是重复的记录. 二.解决 select id from group by id having count(*) > 1 按照id分组并计数,某个id号那一组的数量超过1条则认为重复. http://blog.163.com/ability_money/blog/static/185339259201221443031331/ http://blog.163.com/aner_rui/blog/stat
INSERT INTO hk_test(username, passwd) VALUES ('qmf1', 'qmf1'),('qmf2', 'qmf11') delete from hk_test where username='qmf1' and passwd='qmf1' MySQL里查询表里的重复数据记录: 先查看重复的原始数据: 场景一:列出username字段有重读的数据 select username,count(*) as count from hk_test group by
背景: A表.B表两表关联,关联出来的结果里B表有不止一条,需求是只要B表结果中的某一条(按某字段排序) 经过百度,发现 row_number() over(partition by a order by b desc)函数可用(需要说明下,order by 必须有缺少会报错),以下是数据环境及结果. 创建数据环境 create table A(ANAME varchar(20)); insert into A values('alan'); insert into A values('Ale
用Grid显示数据后,如何让系统自动选取第一条记录呢?在显示Grid时由于其Store正在loading,没法在Grid选取第一条记录,因为还没有记录,所以应在其Store进行操作. 查看Ext.data.Store的load()方法如下: load( [options] )Loads data into the Store via the configured proxy. This uses the Proxy to make an asynchronous call to whatever
CREATE TABLE [dbo].[test1]( [program_id] [int] NULL, [person_id] [int] NULL ) ON [PRIMARY] /*查询每组分组中第一条记录*/ select * from test1 as a where a.person_id in ( person_id from test1 where program_id = a.program_id); select * from ( select ROW_NUMBER() ove
背景: A表.B表两表关联,关联出来的结果里B表有不止一条,需求是只要B表结果中的某一条(按某字段排序) 首先想到了直接写个带排序的子查询去匹配外围的值,从这个结果集中只要第一条,但是经过验证发现,里边的条件是获取不到外层的值的,因此此方案不可行. 经过百度,发现 row_number() over函数可用,以下是数据环境及结果. 创建数据环境 )); insert into A values('alan'); insert into A values('Alee'); insert into
