Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complementmethod is used. Note: All letters in hexadecimal (a-f) must be in lowercase. The hexadecimal string must not contain extra leading 0s. If the num
Division Write a program that finds and displays all pairs of 5-digit numbers that between them use the digits 0through 9 once each, such that the first number divided by the second is equal to an integer N, where. That is, abcde / fghij = N where e
题目: 给定一个整数,将其转换为罗马数字; 题目很简单,主要是依靠整数和罗马数字的对应表: I= 1:V= 5: X = 10: L = 50: C = 100: D = 500: M = 1000 代码如下: public class Solution { public String intToRoman(int num) { if(num <= 0) return ""; String[][] RomanDict = new String[][] { { "&quo
(a) 当n=1时,(10)d=(1010)b 当n=2时,(100)d=(10)d x (10)d=(1010)b x (1010)b 当n=4时,(10000)d=(100)d x (100)d=(1010)b x (1010)b x (1010)b x (1010)b … 因此z=pwr2bin(n/2) T(n)=T(n/2)+(cn/2)log23=>T(n)=O(nlog23) (b) 若十进制整数x的位数等于1,则返回binary[x] 假设位数为n(n>1且n为2的幂),则