18.5 You have a large text file containing words. Given any two words, find the shortest distance (in terms of number of words) between them in the file. If the operation will be repeated many times for the same file (but different pairs of words), c
127. Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the wo
@echo off set path=C:\program files\mysql\mysql server 5.5\bin cd ./ set CURR_PATH=%cd% mysql -h localhost -u root --password=root < crm.sql mysql -h localhost -u root -p CRM < rms.sql --password=root
算法提高 最长单词 时间限制:1.0s 内存限制:512.0MB 编写一个函数,输入一行字符,将此字符串中最长的单词输出. 输入仅一行,多个单词,每个单词间用一个空格隔开.单词仅由小写字母组成.所有单词的长度和不超过100000.如有多个最长单词,输出最先出现的. 样例输入 I am a student 样例输出 student #include<stdio.h> #include<string.h> #define max 100000 int is_zim
题目 Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad
博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech
题目链接 Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach; that is, pack as many words as you can in each line. P
题目内容: dyt喜欢对lrh说的话说反话,现给出lrh说的k句话,输出dyt所说的反话. 输入格式 第一行是样例个数k(k<10) 接下来k行,每行包含lrh说的一句话(每句话长度不超过50,且每句话由英文字母和空格组成(区分大小写),单词间用一个空格隔开,行末无多余空格). 输出格式 针对每一句话,输出dyt所说的反话,每句话占一行. 输入样例 2 hello world here i come zxxz Tql 输出样例 come i here world hello Tql zxxz
描述: 编写程序,读入一行英文(只包含字母和空格,单词间以单个空格分隔),将所有单词的顺序倒排并输出,依然以单个空格分隔. 输入输入为一个字符串(字符串长度至多为100).输出输出为按要求排续后的字符串. 样例输入 I am a student 样例输出 student a am I思路:首先把字符串先反转,从前往后扫,遇到空格处理一下单词,要特别注意:最后一个单词不同于其他单词,要单独处理!代码如下(本代码来自我的老师:http://www.cnblogs.com/huashanqingzhu