题目传送门 大概思路就是把这两个数组排序.在扫描一次,判断大小,累加ans. #include<bits/stdc++.h> using namespace std; int x,y,z; ],m[]; long long s; int main(){ cin>>z>>x>>y; ;i<=z;i++) cin>>n[i]>>m[i]; sort(n+,n++z); sort(m+,m++z); ;i<=z;i++){ if
传送门 题目大意: ai,ai+1,ai+2... 变成 bi,bi+1,bi+2.. 不计顺序,增加和减少a数组均有代价. 题解:贪心+排序 小的对应小的 代码: #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #define N 25009 #define LL long long using namespace std; int n,x,y; LL an
Description You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be described as a line of spots to pile up sand pillars. Spots are numb
Sand Fortress time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimens
Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43
UPDATE: the source code for DbContextScope is now available on GitHub: DbContextScope on GitHub. A bit of context This isn't the first post that has been written about managing the DbContext lifetime in Entity Framework-based applications. In fact, t
(译者注:使用EF开发应用程序的一个难点就在于对其DbContext的生命周期管理,你的管理策略是否能很好的支持上层服务 使用独立事务,使用嵌套事务,并行执行,异步执行等需求? Mehdi El Gueddari对此做了深入研究和优秀的工作并且写了一篇优秀的文章,现在我将其翻译为中文分享给大家.由于原文太长,所以翻译后的文章将分为四篇.你看到的这篇就是是它的第一篇.原文地址:http://mehdi.me/ambient-dbcontext-in-ef6/) 关于DbContext 这不是第一篇
