用matlab画如下图的二叉树. 先按树的先序遍历把结点编号,如下图所示. treeplot函数的序列用如下方法得到.从根结点开始先序遍历,依次写下父结点的编号,设根结点的父结点为0.按先序遍历,根结点的下个结点为2,而结点2的父结点是1,序列变为[0 1].继续先序遍历,下个结点为3,结点3的父结点为2,所以序列变为[0 1 2].继续先序遍历,下个结点为4,结点4的父结点为2,所以序列变为[0 1 2 2].继续先序遍历,下个结点为5,结点5的父结点为1,所以序列变为[0 1 2 2 1].

常用的二维图形命令: plot:绘制二维图形 loglog:用全对数坐标绘图 semilogx:用半对数坐标(X)绘图 semilogy:用半对数坐标(Y)绘图 fill:绘制二维多边填充图形 polar:绘极坐标图   bar:画条形图 stem:画离散序列数据图    stairs:画阶梯图 errorbar:画误差条形图 hist:画直方图 fplot:画函数图 title:为图形加标题 xlabel:在X轴下做文本标记 ylabel:在Y轴下做文本标记 zlabel:在Z轴下做文本标记

原文地址为:Matlab绘制三维曲面(以二维高斯函数为例) 寒假学习了一下Python下的NumPy和pymatlab,感觉不是很容易上手.来学校之后,决定继续看完数字图像处理一书.还是想按照上学期的模式,边看边实现书中的算法.上学期看的时候,是用C语言实现的,发现写程序太耗时间了,所以决定还是学习下Matlab吧(寒假莫有学会Python中的那些库应用...) 经过两天的学习,终于看完了一本关于Matlab的基础书.对于Matlab有了一个基本的了解,感觉Matlab最大的优势在于能够快速的将

Matlab使用bar和barh函数来绘制二维条形图.分别是绘制二维垂直条形图和二维水平条形图. 转自:http://jingyan.baidu.com/article/64d05a02524e63de54f73b76.html 工具/原料 Matlab 方法/步骤   bar(Y):若Y为向量(一维),则分别显示每个分量的高度,横坐标为1到length(Y);如果Y为矩阵,则把Y分解成行向量,在分别画出来.横坐标为矩阵的行数. bar(X,Y):在指定的横坐标上画出Y. bar(X,Y,wid

用matlab绘制箭头 http://npfeng900.blog.163.com/blog/static/14456108201221922944998/ 用matlab绘制箭头1 用matlab绘制箭头 1.    quiver 和quiver3命令 这两个命令适合画关于“场”中向量的图,不适合于画单个剪头,而且放大之后,剪头不是很好看 如: [X,Y] = meshgrid(-2:.2:2); Z = X.*exp(-0.5.*X.^2 - Y.^2); [DX,DY] = gradien

matlab 7.0 绘制二维.三维心形函数       又到周六,下周就要迎来春节小长假了,想想都有些激动.在外漂了一整年,总于可以回家和父母团聚了,还有吃好吃的...,哎呀~想想都流口水呢.不过先不要激动,假期到来前还是要好好工作的,明天周日苦逼的调休...       下面回归正题,聊聊这周想分享的好东西,就是用MATLAB绘制心型图,对!是 ' 心 ' 形的哦~,本人并不是数学专业,只是工作中H5页面做动画有用过动画曲线,比如tween.js,由于底层动画控制逻辑是数学函数.于是回忆起自

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节

3110 二叉堆练习3  时间限制: 3 s  空间限制: 128000 KB  题目等级 : 黄金 Gold 题解       题目描述 Description 给定N(N≤500,000)和N个整数(较有序),将其排序后输出. 输入描述 Input Description N和N个整数 输出描述 Output Description N个整数(升序) 样例输入 Sample Input 5 12 11 10 8 9 样例输出 Sample Output 8 9 10 11 12 数据范围及提

3110 二叉堆练习3 http://codevs.cn/problem/3110/ 题目描述 Description 给定N(N≤500,000)和N个整数(较有序),将其排序后输出. 输入描述 Input Description N和N个整数 输出描述 Output Description N个整数(升序) 样例输入 Sample Input 5 12 11 10 8 9 样例输出 Sample Output 8 9 10 11 12 数据范围及提示 Data Size & Hint 对于3

Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput

Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 这道题让我们求二叉搜索树的某个节点的中序后继节点,那么我们根据BST的性质知道其中序遍历的结果是有序的, 是我最先用的方法是用迭代的中序遍历方法,然后用

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has

Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Follow up: What if the BST is modified (insert/delete operations) often and you nee

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表.数组方便就方便在可以通过index直接访问任意一个元

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要将有序数组转为二叉搜索树,所谓二叉搜索树,是一种始终满足左<根<右的特性,如果将二叉搜索树按中序遍历的话,得到的就是一个有序数组了.那么反过来,我们可以得知,根节点应该是有序数组的中间点,从中间点分开为左右两个有序数组,在分别找出其中间点作为原中间点的左右两个子节点,这不就是是二分查找法的核

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}"

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys

Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 这道题实际上是Catalan Number卡塔兰数的一个例子,如果对卡塔兰数不熟悉的童鞋可能真