public class MultiplicationTable { /** * @description 写一个方法,用一个for循环打印九九乘法表 * @author wangkun * @param args */ public static void main(String[] args) { int i,j; for (i = 1 ; i <= 9 ; i ++){ for(j = 1 ; j <= i ; j ++){ Syst
请使用for循环,倒序打印9×9乘法表. 打印结果如下图所示: 使用for循环打印9×9乘法表 #include <stdio.h> int main() { int i, j, result; for (i = 9; i > 0; i--) { for (j = 1; j <= i; j++) { printf("%d*%d=%d\t", i, j, i * j); } printf("\n"); } return 0; }
--第4题 输出99乘法表 function PrintMulitiplyTable() , do local res = {} local str = "" , i do res[j] = i * j str = table.concat(res, " ") end print(str) end end PrintMulitiplyTable()
一.for循环打印九九乘法表 #注意:由于缩进在浏览器不好控制,请大家见谅,后续会有图片传入. 1.1 左下角 for i in range(1,10): for j in range(1,i+1): print('%d*%d=%2d\t'%(j,i,i*j),end='') print() 效果图: 1.2 右下角 for i in range(1,10): for k in range(i+1,10): print(end=' ') #此处为返回八个空格,请注
用for循环打印九九乘法表: 1 2 3 4 5 6 for i in range (1,10): for j in range(1,10): print(j,"x",i,"=",i*j,"\t",end="") if i==j: print("") break 打印结果是: 1 2 3 4 5 6 7 8 9 1 x
用for循环打印九九乘法表: for i in range (1,10): for j in range(1,10): print(j,"x",i,"=",i*j,"\t",end="") if i==j: print("") break 打印结果是: 1 x 1 = 1 1 x 2 = 2 2 x 2 = 4 1 x 3 = 3 2 x 3 = 6 3 x 3 = 9 1 x 4 = 4 2 x 4 =
题目:http://wenku.baidu.com/view/d66187aad1f34693daef3e8a.html 启动三个线程,分别打印A B C,现在写一个程序 循环打印ABCABCABC.... 本文分别使用wait.nofity和Semaphore来实现: wait.nofity版本 public class TestThread { public static void main(String[] args) { new Thread(new OrderThread(0,'A')