矩阵快速幂代码: int n; // 所有矩阵都是 n * n 的矩阵 struct matrix { int a[100][100]; }; matrix matrix_mul(matrix A, matrix B, int mod) { // 2 个矩阵相乘 matrix C; for (int i = 0; i < n; ++i) { for (int j = 0; j < n; ++j) { C.a[i][j] = 0; for (int k = 0; k < n; ++k) {
Matrix Power Series Time Limit: 3000MS Memory Limit: 131072K Total Submissions: 15417 Accepted: 6602 Description Given a n × n matrix A and a positive integer k, find the sum S = A + A2 + A3 + - + Ak. Input The input contains exactly one test cas