关注微信公众号:CodingTechWork,一起学习进步. 引言 在线上运维的过程中,遇到一个头疼的事情,有一些合作公司的数据直接从平台上down下来是一个excel,然后发到研发手里去数据库中核对是否存在,怎么办呢?一般死脑筋方法就是使用sql语句select * from tb_name where colume_name="xxx";去核对是否存在该记录,完了,完全陷入到非sql不可的坑了. 在思考如何更好的去比对两堆类型相同的数据时,除了程序员用后端的方法(不管是sql
#接口返回值 list1 = ['张三', '李四', '王五', '老二'] #数据库返回值 list2 = ['张三', '李四', '老二', '王七'] a = [x for x in list1 if x in list2] #两个列表表都存在 b = [y for y in (list1 + list2) if y not in a] #两个列表中的不同元素 print('a的值为:',a) print('b的值为:',b) c = [x for x in list1 if x no
[抄题]: Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &q
/* * TestList.java * Version 1.0.0 * Created on 2017年12月15日 * Copyright ReYo.Cn */ package reyo.sdk.utils.test.list2; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map; public class TestList { public st
We are given two sentences A and B. (A sentence is a string of space separated words. Each word consists only of lowercase letters.) A word is uncommon if it appears exactly once in one of the sentences, and does not appear in the other sentence. R