You are given a rooted tree with root in vertex 1. Each vertex is coloured in some colour. Let's call colour c dominating in the subtree of vertex v if there are no other colours that appear in the subtree of vertex v more times than colour c. So it'
一个比较显然的做法:对每棵子树用线段树维护其中的深度,线段树合并即可. 本来想用这个题学一下dsu on tree,结果还是弃疗了. #include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<algorithm> using namespace std; int read() { ,f=;char c
将所有串(包括S)放一块建SAM.对于询问,倍增定位出该子串所在节点,然后要查询的就是该子串在区间内的哪个字符串出现最多.可以线段树合并求出该节点在每个字符串中的出现次数. #include<bits/stdc++.h> using namespace std; #define ll long long #define N 1100010 char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c