class Demo{ public static void main(String[] args){ int i =2584; //do{ int g = i%10; int s = (i%100)/10; int b = (i%1000)/100; int q = i/1000; System.out.println(g); System.out.println(s); System.out.println(b); System.out.println(q); //}while(i <= 1
Scanner inn = new Scanner(System.in); int i = inn.nextInt(); System.out.println("个位是"+i%10+"十位是"+i/10%10+"百位是"+i/100%10+"千位是"+i/1000%10); Scanner inn = new Scanner(System.in); String s = inn.next(); for (int i=0;i&l
题目:编程求解,输入两个整数n和m,从数列1,2,3,……n中随意取几个数,使其和等于m.要求将所有的可能组合列出来. 分析:分治的思想.可以把问题(m,n)拆分(m - n, n -1)和(m, n - 1). 注意点:1.n大于m时,可直接从n = m出开始搜索 2.结束条件:n < 1 || m < 1 3.打印输出结果.注意打印输出结果并不代表函数调用结束,以n = 7 和 m = 10为例,7.3和7.2.1都是一种结果,不能得到7.3的时候终止.打印输出的条件是n = m 程序代码
//从数列1,2,3.......n 中 随意取几个数,使其和等于 m public static void Print(int n, int m, List<int> list = null) { if (n < 1 || m < 1) { return; } for (int i = 1; i <= n; i++) {
D. Black Hills golden jewels time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output In Rapid City are located the main producers of the Black Hills gold jewelry, a very popular product among tour
import java.util.LinkedList; import java.util.Scanner; public class Main { private static LinkedList<Integer> list = new LinkedList<>(); public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while (scanner.hasNext(
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApp1 { class Program { static void Main(string[] args) { // 防止出现随机值无法组合 ) { Con = ; // 初始化数组长度 ; Arr = new int[Len]; Temp = new int[Con]; // 最小的数 )
