Oil Deposits Time Limit: 2 Seconds Memory Limit: 65536 KB The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid th
Oil Deposits Time Limit: 1000MS Memory Limit: 10000K Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid
HDU 1241 Oil Deposits L -DFS Time Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64u Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large r
Oil Deposits The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It
迷宫城堡 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11231 Accepted Submission(s): 5030 Problem Description 为了训练小希的方向感,Gardon建立了一座大城堡,里面有N个房间(N<=10000)和M条通道(M<=100000),每个通道都是单向的,就是说若称某通道连通了A
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyze
本题是一道连通块的入门题,用来练手,后续还会更新连通块的题目. 本题大意:一个n * m 的陆地上面有很多水洼,让你统计水洼的个数并输出. 本题思路:按照顺序遍历陆地,如果发现水洼就将它的八连块都进行探索,发现水洼就继续探索,直到一片大水洼都被探索完,就继续进行其他搜索,DFS. 代码: #include <cstdio> using namespace std; + ; char field[maxn][maxn]; int n, m, ans; void dfs(int u, int v)
一.题面 here 二.分析 这题刚开始没读懂题意,后来明白了,原来就是一个数连通块里点数的问题.首先在建图的时候,只考虑红色路径上的点.为什么呢,因为为了不走红色的快,那么我们可以反着想只走红色的路径,这样把所有的可能数再减去只走红色路径的数就是最终的答案了.这里要注意的是,如果连通块里只有一个点,那么就是K个点都是这个点的情况,根据题意是不满足的,也要减去. 三.AC代码 #include<bits/stdc++.h> using namespace std; typedef long l