题目: 给定一个数组,求如果排序之后,相邻两数的最大差值,要求时间复杂度为O(N),且要求不能用非基于比较的排序 public static int maxGap(int nums[]) { if (nums == null || nums.length < 2) { return 0; } int len = nums.length; int max = Integer.MIN_VALUE; int min = Integer.MAX_VALUE; for (int i = 0; i < l
Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 67252 Accepted Submission(s): 28829 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m
译者按: 有时候一个算法的直观.简洁.高效是需要作出取舍的. 原文: FUNCTIONAL JAVASCRIPT: FIVE WAYS TO CALCULATE AN AVERAGE WITH ARRAY REDUCE 译者: Fundebug 本文采用意译,版权归原作者所有 函数式编程中用于操作数组的方法就像"毒品"一样,它让很多人爱上函数式编程.因为它们真的十分常用而且又超级简单. .map() 和 .filter()都仅需一个参数,该参数定义操作数组每一个元素的函数即可.redu
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m