题意: 输入两个分数(分子分母各为一个整数中间用'/'分隔),输出它们的四则运算表达式.小数需要用"("和")"括起来,分母为0的话输出"Inf"(输入的分母保证不为0). trick: 测试点2很容易溢出,建议遇到乘法时先化简分数并且不要用相乘小于零来判断异号. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespac

1088 Rational Arithmetic(20 分) For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in o

For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational number

For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational number

题目 For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, diference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational numb

输入为两个分数,让你计算+,-,*,\四种结果,并且输出对应的式子,分数要按带分数的格式k a/b输出如果为负数,则带分数两边要有括号如果除数为0,则式子中的结果输出Inf模拟题最好自己动手实现,考验细节处理,其它没啥好说的. #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> using namespace std; ]; ]; long long GC

题意: 给出两个分式(a1/b1 a2/b2),分子.分母的范围为int型,且确保分母不为0.计算两个分数的加减乘除,结果化为最简的形式,即"k a/b",其中若除数为0的话,输出Inf. 思路: 分数四则运算的模板题.分析详见:基础数学问题 代码: #include <stdio.h> #include <string.h> #include <stdlib.h>//abs() typedef long long LL; struct Fracti

简单题. 注意:读入的分数可能不是最简的.输出时也需要转换成最简. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algor

1.注意在数字和string转化过程中,需要考虑数字不是只有一位的,如300转为"300",一开始卡在里这里, 测试用例: 24/8 100/10 24/11 300/11 2.该题用到了欧几里德算法求最小公约数gcd(a,b) 算法如下: //欧几里德算法求最大公约数gcd,其中a>b long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a%b); } AC代码如下: //#include&l

1088. Rational Arithmetic (20) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Spe

1088. Rational Arithmetic (20) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Spe

Source: PAT A1088 Rational Arithmetic (20 分) Description: For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one

For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational number

题目描写叙述 For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. 输入描写叙述: Each input file contains one test case, which gives in one line the two rational numbers in t

For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational number

Input The first line of input contains one integer, giving the number of operations to perform. Then follow the operations, one per line, each of the form x1 y1 op x2 y2. Here, −109≤x1,y1,x2,y2<109 are integers, indicating that the operands are x1/y1

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain

2019/4/3 1063 Set Similarity n个序列分别先放进集合里去重.在询问的时候,遍历A集合中每个数,判断下该数在B集合中是否存在,统计存在个数(分子),分母就是两个集合大小减去分子. // 1063 Set Similarity #include <set> #include <map> #include <cstdio> #include <iostream> #include <algorithm> using name

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了

本文为PAT甲级分类汇编系列文章. 计算类,指以数学运算为主或为背景的题. 题号 标题 分数 大意 1058 A+B in Hogwarts 20 特殊进制加法 1059 Prime Factors 25 分解素因数 1060 Are They Equal 25 一定精度下两数是否相等 1065 A+B and C (64bit) 20 大数加法与比较 1069 The Black Hole of Numbers 20 黑洞数 1073 Scientific Notation 20 科学计数法还