2018 ACM-ICPC 中国大学生程序设计竞赛线上赛:https://www.jisuanke.com/contest/1227 题目链接:https://nanti.jisuanke.com/t/26219 Rock Paper Scissors Lizard Spock Description: Didi is a curious baby. One day, she finds a curious game, which named Rock Paper Scissors Lizard

2018 ACM-ICPC 中国大学生程序设计竞赛线上赛:https://www.jisuanke.com/contest/1227 题目链接:https://nanti.jisuanke.com/t/26172 Clever King Description: In order to increase the happiness index of people's lives, King Y has decided to develop the manufacturing industry v

若干年之前的一道题,当时能写出来还是超级开心的,虽然是个板子题.一直忘记写博客,备忘一下. 米勒拉判大素数,关于米勒拉宾是个什么东西,传送门了解一下:biubiubiu~ B. Goldbach 题目传送门 自己看题意吧,直接贴代码了. 代码: #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<cstdlib> #include<al

Description: There is a positive integer X, X's reversion count is Y. For example, X=123, Y=321; X=1234, Y=4321. Z=(X-Y)/9, Judge if Z is made up of only one number(0,1,2...9), like Z=11,Z=111,Z=222,don't consider '+'and '-'. Input: Input contains of

Description: The elderly aunts always like to look for bargains and preferential merchandise. Now there is a shop carrying out group purchase promotion. Rules are as follows : There are r pieces of promotional items, and each item is only one. In the

A------------------------------------------------------------------------------------ 题目链接:http://202.197.224.59/OnlineJudge2/index.php/problem/read/id/1260 题解:随机 n 个数把矩阵补全成 n × n 的.那么就是要算伴随矩阵的第一行,也就是逆矩阵的第一列,高斯消元即可. 源码:(Q神写的高斯消元,先贴一下诶,待补) #include<cs

有时候,很简单的模板题,可能有人没有做出来,(特指 I ),到时候一定要把所有的题目全部看一遍 目录 B 题解 E F 题解 H I 题解&代码 J B 输入样例 3 2 1 2 1 2 3 1 输出样例 1 说明 In the first sample case, the sequence [a1,a2,a3]=[0,1,0][a_1,a_2,a_3]=[0,1,0][a1,a2,a3]=[0,1,0] meets all the constraints and has the minimum

题目传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6438 Buy and Resell Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1233    Accepted Submission(s): 407 Problem Description The Power Cube is used

题目传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6447 YJJ's Salesman Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 919    Accepted Submission(s): 290 Problem Description YJJ is a salesman who h

Tree and Permutation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 619    Accepted Submission(s): 214 Problem Description There are N vertices connected by N−1 edges, each edge has its own len

链接:https://www.nowcoder.com/acm/contest/163/F 来源:牛客网 2018 ACM 国际大学生程序设计竞赛上海大都会赛重现赛 F Color it 时间限制:C/C++ 3秒,其他语言6秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 There is a matrix A that has N rows and M columns. Each grid (i,j)(0 ≤ i < N,

2018 ACM 国际大学生程序设计竞赛上海大都会赛重现赛 F Color it (扫描线) 链接:https://ac.nowcoder.com/acm/contest/163/F来源:牛客网 时间限制:C/C++ 3秒,其他语言6秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 There is a matrix A that has N rows and M columns. Each grid (i,j)(0 ≤ i

2018 ACM 国际大学生程序设计竞赛上海大都会赛重现赛 J Beautiful Numbers (数位DP) 链接:https://ac.nowcoder.com/acm/contest/163/J?&headNav=acm来源:牛客网 时间限制:C/C++ 8秒,其他语言16秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 NIBGNAUK is an odd boy and his taste is strange a

传送门:2018 ACM 国际大学生程序设计竞赛上海大都会赛 2018 ACM 国际大学生程序设计竞赛上海大都会赛重现赛2018-08-05 12:00:00 至 2018-08-05 17:00:00时长: 5小时 比赛情况 实录 难度差不多介于省赛和区域赛之间吧.开题A是计算几何,有点思路后就先放下去写签到题,B读错题WA一发,K直接套模板,然后就接着看A.之前写过类似题,没注意数据范围就头铁地交了发n3的代码,TE后才发现数据范围是之前那道十多倍,就听学长的先看D.推十分钟公式无果后打算直

朋友 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description B君在围观一群男生和一群女生玩游戏,具体来说游戏是这样的:给出一棵n个节点的树,这棵树的每条边有一个权值,这个权值只可能是0或1. 在一局游戏开始时,会确定一个节点作为根.接下来从女生开始,双方轮流进行 操作.当一方操作时,他们需要先选择一个不为根的点,满足该点到其父亲的边权为1; 然

最大的位或 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description B君和G君聊天的时候想到了如下的问题.给定自然数l和r ,选取2个整数x,y满足l <= x <= y <= r ,使得x|y最大.其中|表示按位或,即C. C++. Java中的|运算.   Input 包含至多10001组测试数据.第一行有一个正整数,表示数据的组数.

异或密码 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description 晨晨在纸上写了一个长度为N的非负整数序列{ai}.对于这个序列的一个连续子序列{al,al+1,-,ar}晨晨可以求出其中所有数异或的结果 alxoral+1xor...xorar其 中xor表示位异或运算,对应C.C++. Java等语言中的^运算.小璐提出了M个询问,每个询问用

传递 Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)     Problem Description 我们称一个有向图G是传递的,当且仅当对任意三个不同的顶点a,,若G中有 一条边从a到b且有一条边从b到c ,则G中同样有一条边从a到c.我们称图G是一个竞赛图,当且仅当它是一个有向图且它的基图是完全图.换句 话说,将完全图每条边定向将得到一个竞赛图.下图展示的是一个有4个顶点

扫雷 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 998    Accepted Submission(s): 289 Problem Description 扫雷游戏是晨晨和小璐特别喜欢的智力游戏,她俩最近沉迷其中无法自拔.该游戏的界面是一个矩阵,矩阵中有些格子中有一个地雷,其余格子中没有地雷. 游戏中,格子可能处于己知和未知的状态

Equation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 92    Accepted Submission(s): 24 Problem Description Little Ruins is a studious boy, recently he learned addition operation! He was rewa