/*<说明> 编程实现将字符串中最短的单词输出,在主函数中输入字符串,编写一个函数完成最短单词的查找 </说明>*/ #include<time.h> #include<iostream> using namespace std; void shortestWord(char* in) { ; ]; ;*(;i++) { if(*(in+i)==' ') { o[j]=i; //o的作用是定位每一个空格的位置 通过空格位置间隔的大小判断单词的长短 j++;

25:最长最短单词 总时间限制:  1000ms 内存限制:  65536kB 描述 输入1行句子(不多于200个单词,每个单词长度不超过100),只包含字母.空格和逗号.单词由至少一个连续的字母构成,空格和逗号都是单词间的间隔. 试输出第1个最长的单词和第1个最短单词. 输入 一行句子. 输出 两行输出:第1行,第一个最长的单词.第2行,第一个最短的单词. 样例输入 I am studying Programming language C in Peking University 样例输出 P

noi25 最长最短单词(为什么会出现运行时错误) 一.总结 一句话总结:比如除以零,数组越界,指针越界,使用已经释放的空间,数组开得太大,超出了栈的范围,造成栈溢出 1.c++报runtime error是什么意思? runtime error (运行时错误)就是程序运行到一半,程序就崩溃了. 2.为什么会出现运行时错误? ①除以零 ②数组越界:int a[3]; a[10000000]=10; ③指针越界:int * p; p=(int *)malloc(5 * sizeof(int));

This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be

This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list

/*===================================== 最长单词2 总时间限制: 1000ms 内存限制: 65536kB 描述 一个以'.'结尾的简单英文句子,单词之间用空格分隔,没有缩写形式和其它特殊形式 输入 一个以'.'结尾的简单英文句子(长度不超过500),单词之间用空格分隔,没有缩写形式和其它特殊形式 输出 该句子中最长的单词.如果多于一个,则输出第一个 样例输入 I am a student of Peking University. 样例输出 Univer

This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list

This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be

Design a class which receives a list of words in the constructor, and implements a method that takes two words word1 and word2 and return the shortest distance between these two words in the list. Your method will be called repeatedly many times with

要求: 设计一个算法从一片英语文章或者英语字符串里面输出其中最长的单词. Input: string     Output: string 尽可能多的设计测试用例来测试这个算法. 考虑空间和时间复杂度看作是一个加分项 Version1.0 using System; namespace GetLongestWord { class Program { static void Main(string[] args) { Console.WriteLine("Please input a strin

Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. For example,Assume that words = ["practice", "makes", "perfect", "coding", "makes"]. G

This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list

This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be

最短单词路径 127. Word Ladder (Medium) Input: beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"] Output: 5 Explanation: As one shortest transformat

返回提供的句子中最长的单词的长度. 返回值应该是一个数字. 第一步,使用String.prototype.split()方法将字符串转换成数组 function findLongestWord(str) { var arr = str.split(' '); console.log(arr) } findLongestWord("The quick brown fox jumped over the lazy dog"); 从结果中可以看出,返回的数组length为9 第二步,循环数组

首先,要求找到最长最短字符串,我们应该用数组将其存起来,输入的个数是不固定的,我们就可以用Scanner获取要输入的个数,最终找到的个数也不固定,我们可以封装两个方法,并且返回值类型为数组. 我遇到的问题,开始我想到的是字符串拼接,么想到返回值用数组存,导致每次返回的个数都是固定的,就算有多个. 代码如下: import java.util.Scanner; //输入n行字符串,找出最长最短字符串(若有个数相同的,都打印出来) public class FindString { public s

720. 词典中最长的单词 给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 示例 1: 输入: words = ["w","wo","wor","worl", "world"] 输出: "world" 解释: 单词"

[九度OJ]题目1195:最长&最短文本 解题报告 标签(空格分隔): 九度OJ http://ac.jobdu.com/problem.php?pid=1195 题目描述: 输入多行字符串,请按照原文本中的顺序输出其中最短和最长的字符串,如果最短和最长的字符串不止一个,请全部输出. 输入: 输入包括多行字符串,字符串的长度len,(1<=len<=1000). 输出: 按照原文本中的顺序输出其中最短和最长的字符串,如果最短和最长的字符串不止一个,请全部输出. 样例输入: hello

5.7 Given a list of words, write a program to find the longest word made of other words in the list. 这道题给了我们一个字符串数组,让我们找到最长的那个单词是由字符串数组中的其他单词组成的,LeetCode上跟类似的题目有Word Break和Word Break II.那么我们首先来想如果是拆分两个单词怎么做,那我们要首先把所有的单词存到哈希表里,然后遍历每个单词,每个位置上都拆分成左右两个字符

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l