我想很多人第一次学习递归的时候,老师或者书本上可能会举汉诺塔的例子. 但是今天,我们讨论的重点不是简单的汉诺塔算法,而是三柱汉诺塔的延伸.先来看看经典的三柱汉诺塔. 一.三柱汉诺塔(Hanoi_Three): 我想大家对于三柱汉诺塔的理解以及算法的实现应该是很熟练了. 我在这里简单的过一遍三柱汉诺塔的算法思想: 有A.B.C三根柱子,A柱上有n个盘子,现在需要将A上所有的盘子转移到C上,请给出搬运次数最少的步骤. 算法思想: 1.将A上n-1个盘子以C为缓存,全部转移到 B 柱上. 2.将A上留

reference:递归函数 Note 1.在函数内部,可以调用其他函数.如果一个函数在内部调用自身本身,这个函数就是递归函数. eg.计算阶乘: #!/usr/bin/env python3 def my_func(n) : if n == 1 : return 1 return n * my_func(n-1) output: >>> from function4 import my_func >>> my_func(1) 1 >>> my_fun

Hanoi Tower Troubles Again! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 602    Accepted Submission(s): 418 Problem Description People stopped moving discs from peg to peg after they know the

链接:ZOJ1239 Hanoi Tower Troubles Again! Description People stopped moving discs from peg to peg after they know the number of steps needed to complete the entire task. But on the other hand, they didn't not stopped thinking about similar puzzles with

A. Hanoi tower Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100114 Description you the conditions of this task. There are 3 pivots: A, B, C. Initially, n disks of different diameter are placed on the pivot A: the smallest dis

电影<猩球崛起>刚开始的时候,年轻的Caesar在玩一种很有意思的游戏,就是汉诺塔...... 汉诺塔源自一个古老的印度传说:在世界的中心贝拿勒斯的圣庙里,一块黄铜板上插着三支宝石针.印度教的主神梵天在创造世界的时候,在其中一根针上从下到上穿好了由大到小的64片金片,这就是所谓的汉诺塔(Hanoi Tower).不论白天黑夜,总有一个僧侣在按照下面的法则移动这些金片:一次只移动一片,不管在哪根针上,小片必须在大片上面. 僧侣们预言,当所有的金片从梵天穿好的金片上移到另一根针上时,世界末日就会来

Hanoi Tower Troubles Again! Problem Description People stopped moving discs from peg to peg after they know the number of steps needed to complete the entire task. But on the other hand, they didn't not stopped thinking about similar puzzles with the

课本源码部分 第3章  栈和队列 - 汉诺塔(Hanoi Tower)问题 ——<数据结构>-严蔚敏.吴伟民版        源码使用说明  链接☛☛☛ <数据结构-C语言版>(严蔚敏,吴伟民版)课本源码+习题集解析使用说明        课本源码合辑  链接☛☛☛ <数据结构>课本源码合辑        习题集全解析  链接☛☛☛ <数据结构题集>习题解析合辑        本源码引入的文件  链接☛ 无外链       文档中源码及测试数据存放目录:数据

1028. Hanoi Tower Sequence Constraints Time Limit: 1 secs, Memory Limit: 32 MB Description Hanoi Tower is a famous game invented by the French mathematician Edourard Lucas in 1883. We are given a tower of n disks, initially stacked in decreasing size

Hanoi Tower Time Limit: 2 Seconds Memory Limit: 65536 KB You all must know the puzzle named "The Towers of Hanoi". The puzzle has three pegs (peg 1, peg 2 and peg 3) and N disks of different radii. Initially all disks are located on the first pe

People stopped moving discs from peg to peg after they know the number of steps needed to complete the entire task. But on the other hand, they didn't not stopped thinking about similar puzzles with the Hanoi Tower. Mr.S invented a little game on it.

前言 回家休息第3天了,状态一直不是太好,主要是要补牙,检查身体,见同学见亲戚,心里又着急校招,难得能腾出时间来好好思考,这里也是看<cracking the coding interview>,看到了汉诺塔问题,这里记录一下 思路分析 汉诺塔是递归的经典题目,这里先介绍使用递归的关键: 使用递归的一个关键就是:我们先定义一个函数,不要着急去实现它,但是要明确它的功能 对于汉诺塔问题,我们定义如下函数原型: void hanoi(char src, char mid, char dst, in

[题目描述] In the classic problem of Towers of Hanoi, you have 3 towers and N disks of different sizes which can slide onto any tower. The puzzle starts with disks sorted in ascending order of size from top to bottom (i.e., each disk sits on top of an ev

汉诺塔问题源于印度的一个古老传说:梵天创造世界的时候做了三根金刚石柱子,在一根柱子上从下往上按照大小顺序摞着64片黄金圆盘.梵天命令婆罗门把圆盘按大小顺序重新摆放在另一根柱子上,并且规定小圆盘上不能放大圆盘,在三根柱子之间一次只能移动一个圆盘.当所有的黄金圆盘都重新摆放在另一根柱子上时,世界就将在霹雳声中毁灭,梵塔.庙宇和众生都将同归于尽. 假设A是起始柱,B是中间柱,C是目标柱. 从最简单的例子开始看: 如果A柱上只剩一个圆盘,那么将圆盘从A柱移到C柱即可. (A --> C) 如果A柱上剩两

Description In the classic problem of Towers of Hanoi, you have 3 towers and N disks of different sizes which can slide onto any tower. The puzzle starts with disks sorted in ascending order of size from top to bottom (i.e., each disk sits on top of

In the classic problem of Towers of Hanoi, you have 3 towers and N disks of different sizes which can slide onto any tower. The puzzle starts with disks sorted in ascending order of size from top to bottom (i.e., each disk sits on top of an even larg

水题,搞清楚hanoi的定义就好做了. /* 1329 */ #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #define MAXN 55 int b[MAXN]; int a[MAXN]; bool isSquare(int x) { int y = (int) sqrt(x*1.0); return y*y == x; } void init() { in

Hanoi Towers Time Limit : 10000/5000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 0 Accepted Submission(s) : 0 Special Judge Problem Description The “Hanoi Towers” puzzle consists of three pegs (that we will name A,

#include<stdio.h>void move(int n,char a,char b){ printf("将第%d个盘子从%c移动到%c\n",n,a,b); return;} void hanoi(int n,char a,char b,char c){ if(n==1){  move(n,a,c);  return; } hanoi(n-1,a,c,b); move(n,a,c); hanoi(n-1,b,a,c);} int main(){ int n; sc

找规律的题目an=an-1+(i+i%2)/2*2; ;}

汉诺塔问题 1.问题来源:汉诺塔来源于印度传说的一个故事,上帝创造世界时作了三根金刚石柱子,在一根柱子上从上往下从小到大顺序摞着64片黄金圆盘.上帝命令婆罗门把圆盘从下面开始按大小顺序重新摆放在另一根柱子上.并且规定,在小圆盘上不能放大圆盘,在三根柱子之间一回只能移动一个圆盘,只能移动在最顶端的圆盘. 2.问题分析: 汉诺塔问题的以下几个限制条件: 1.在小圆盘上不能放大圆盘. 2.在三根柱子之间一回只能移动一个圆盘. 3.只能移动在最顶端的圆盘.   案例 1 - 假设只有一个盘子的时候, 盘