Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The minimum absolute difference is 1, which is the difference between 2 and 1
题目230. 二叉搜索树中第K小的元素 给定一个二叉搜索树,编写一个函数 kthSmallest 来查找其中第 k 个最小的元素. 题解 中序遍历BST,得到有序序列,返回有序序列的k-1号元素. 代码 class Solution { public int kthSmallest(TreeNode root, int k) { List<Integer> list = new LinkedList<>(); inorder(root,list); return list.get(
Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The minimum absolute difference is 1, which is the difference between 2 and 1
Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The minimum absolute difference is 1, which is the difference between 2 and 1
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has
03-树1. List Leaves (25) Given a tree, you are supposed to list all the leaves in the order of top down, and left to right. Input Specification: Each input file contains one test case. For each case, the first line gives a positive integer N (<=10) wh
假设关键字的总数为n,用c[i,j]表示第i个关键字到第j个关键字的最优二叉查找树的代价,我们的目标是求c[0,n-1].要求c[i,j],首先要从第i个关键字到第j个关键字中选一个出来作为根结点,选出根结点后,最优二叉搜索树的代价为左子树的代价加上右子树的代价,由于每选出一个根结点,每个关键字的搜索长度都增加1,因此得出递推式,即当 package org.xiu68.ch06.ex6; public class Ex6_20 { //动态规划,最优二叉搜索树 public static vo