今天,还是国庆和中秋双节的时间节点,一个天气不错的日子,孩子已经早早的睡觉了,玩了一整天,也不睡觉,累的实在扛不住了,勉强洗澡结束,倒床即睡着的节奏... 不多说题外话,进入正题. 什么是A*搜索算法呢?就用百科的解说吧: A*算法,A*(A-Star)算法是一种静态路网中求解最短路径最有效的直接搜索方法,也是解决许多搜索问题的有效算法.算法中的距离估算值与实际值越接近,最终搜索速度越快. A*搜索的实际应用场景很多,但是大家最为熟悉的恐怕莫过于游戏了.典型的游戏就是穿越障碍寻宝,要求在最少的代

|—search()—|—添加一个列表变量Expend,存储每个小格扩展时为第几步,可打印出 |                    |—打印运动表 |—A*—|— heuristic() |—Dynamic programming(动态规划)—|—Value编程 |                                                           |—应用于现实 |                                              

想着CSDN还是不适合做论文类的笔记,那里就当做技术/系统笔记区,博客园就专心搞看论文的笔记和一些想法好了,[]以后中框号中间的都算作是自己的内心OS 有时候可能是问题,有时候可能是自问自答,毕竟是笔记嘛 心路历程记录:然后可能有很多时候都是中英文夹杂,是因为我觉得有些方法并没有很好地中文翻译的意思(比如configuration space),再加上英文能更好的搜索.希望大家能接受这种夹杂写法,或者接受不了的话直接关掉这个看原文 前言:这是一篇02年的关于Motion Planning - P

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节

题目链接:Recover Binary Search Tree | LeetCode OJ Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constan

题目链接:Validate Binary Search Tree | LeetCode OJ Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right

http://www.hightopo.com/demo/astar/astar.html 最近搞个游戏遇到最短路径的常规游戏问题,一时起兴基于HT for Web写了个A*算法的WebGL 3D呈现,算法基于开源 https://github.com/bgrins/javascript-astar 的javascript实现,其实作者也有个不错的2D例子实现 http://www.briangrinstead.com/files/astar/ ,只不过觉得所有A*算法的可视化实现都是平面的不够

Sept. 22, 2015 学一道算法题, 经常回顾一下. 第二次重温, 决定增加一些图片, 帮助自己记忆. 在网上找他人的资料, 不如自己动手. 把从底向上树的算法搞通俗一些. 先做一个例子: 9/22/2015 Go over one example to build some muscle memory about this bottom up, O(1) solution to find the root node in subtree function. Sorted List: 1

Given a non-empty binary search tree and a target value, find k values in the BST that are closest to the target. Note: Given target value is a floating point. You may assume k is always valid, that is: k ≤ total nodes. You are guaranteed to have onl

Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target.

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has

Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le

Design a data structure that supports the following two operations: void addWord(word) bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表.数组方便就方便在可以通过index直接访问任意一个元

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要将有序数组转为二叉搜索树,所谓二叉搜索树,是一种始终满足左<根<右的特性,如果将二叉搜索树按中序遍历的话,得到的就是一个有序数组了.那么反过来,我们可以得知,根节点应该是有序数组的中间点,从中间点分开为左右两个有序数组,在分别找出其中间点作为原中间点的左右两个子节点,这不就是是二分查找法的核

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}"

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys