Private Sub Form_Load() '引用C:\windows\system32\MSCOMCTL.OCX,否则提示出错. Dim Rec As New ADODB.Recordset Dim stRecQL As String Dim Item As Integer Dim i As Integer Dim Node1 As Node Rec.Open "GoodsCategoryQ", CurrentProject.Connection, adOpenKeyset, a
TreeView设置节点图标 没子节点的设置其图标为 0 有节点的设置其图标为 1 procedure TForm1.Button1Click(Sender: TObject);var i:Integer;begin with TreeView1 do begin for i:= 0 to Items.Count -1 do begin if Items[i].HasChildren then begin
TreeView 树节点的处理 using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Threading.Tasks; using System.Windows.Forms; using WinForm_CRUD.B
以下两种方法哪个不报错就用哪个.用法都是在TreeView标签中加入OnClick="",然后引入函数名即可 第一种方法:(摘自:http://www.cnblogs.com/freeliver54/archive/2007/09/04/881024.html) <script type ="text/javascript" > function postBackByObject() { var o = window.
using System;using System.Collections.Generic;using System.ComponentModel;using System.IO;using System.Drawing;using System.Linq;using System.Text;using System.Threading.Tasks;using System.Windows.Forms; namespace C11_资源管理器{ public partial class Form
treeview.nodes是获取下一级所有子节点,但是如果是多层的话,就不能,想个法子来获取所有的节点(含节点的子节点),想了想 还是替归算法比较方便,如是有了下面的代码 public static List<TreeNode> getAllNodes(TreeNodeCollection node) { List<TreeNode> lst = new List<TreeNode>(); foreach (TreeNode n in node) { if (!lst