思路:dp[i][x][y]表示第i个序列中,右脚在x位置,左脚在y位置时,其最小花费. 那么dp[i][x][y]=min(dp[i-1][a[i]][y]+cost[a[i]][x],dp[i-1][x][a[i]]+cost[a[i]][y]); 题目连接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=32 #incl

http://www.talkwithtrend.com/Article/147961 AIX系统时区总结 字数 2078阅读 5844评论 0赞 0 前几天NTP的问题牵涉出时区问题,大家可能被眼花缭乱的时区格式给搞糊涂,来看看: #echo $TZ BEIST-8 GMT-8 Asia/Shanghai #date 执行结果的时区格式如下 BEIST GMT CST或GMT+8:00 晕了吧,先看看几个概念 1.GMT(Greenwich Mean Time)代表格林尼治标准时间详情可以go

Mysql默认时区格式是'+8:00'的格式,这个时区可以在my.ini中[mysqld]节点下设置 default-time-zone = '+8:00' 默认这个设置是没有的 但是mysql不支持'Asia/Shanghai'这种时区格式 执行下面sql语句是报错的 SET GLOBAL time_zone = 'Asia/Shanghai' 解决方法 到https://dev.mysql.com/downloads/timezones.html下载时区文件 如果你的mysql版本是5.7及

连接mysql库报的异常信息: org.springframework.transaction.CannotCreateTransactionException: Could not open JDBC Connection for transaction; nested exception is org.apache.commons.dbcp.SQLNestedException: Cannot create PoolableConnectionFactory (Cannot load con

linux date 显示指定时区的时间 借助TZ 环境变量 export TZ=Asia/Shanghai 或 America/New_York 2015-02-10 10:58:22 youcharming 阅读数 14670 文章标签: linuxdate显示指定时区TZ环境变量 更多 分类专栏: linux系统   版权声明:本文为博主原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明. 本文链接:https://blog.csdn.net/youcharmi

The Preliminary Contest for ICPC Asia Shanghai 2019 C Triple(FFT+暴力) 传送门:https://nanti.jisuanke.com/t/41400 题意: 给你三个数组a,b,c,要你求有多少个三元组(i,j,k),使得 \[ \begin{array}{l}{\left|A_{i}-B_{j}\right| \leq C_{k}, \text { and }} \\ {\left|B_{j}-C_{k}\right| \leq

<?php function changeTimeZone($date_time, $format = 'Y-m-d H:i:s', $to = 'Europe/Rome', $from = 'Asia/Shanghai') { $datetime = new DateTime($date_time, new DateTimeZone($from)); $datetime->setTimezone(new DateTimeZone($to)); return $datetime->for

调查系统错误时,发现了一个很奇怪的现象,出生日期1986-05-04号的用户始终无法注册.发现后台使用使用jodatime的代码demo如下: public static DateTime parseDatetime(String time, String format) { DateTimeFormatter formatter = DateTimeFormat.forPattern(format); return formatter.parseDateTime(time); } 后台抛出了异

项目报错信息: Connot parse "1991-04-14",illegal instant due to time zone offset transition(Asia/Shanghai) 在网上查了一下说是由于夏令时问题引起了,那么什么是夏令时呢? 夏时制,夏时令(Daylight Saving Time:DST),又称“日光节约时制”和“夏令时间”,是一种为节约能源而人为规定地方时间的制度,在这一制度实行期间所采用的统一时间称为“夏令时间”.一般在天亮早的夏季人为将时间调

问题背景 这里讲解了如何同步容器和主机的时间:https://www.cnblogs.com/poloyy/p/13967532.html 其中使用方法二 docker cp /etc/localtime [容器ID或名字]:/etc/localtime 报错了 解决方案 docker cp /usr/share/zoneinfo/Asia/Shanghai gitlab:/etc/localtime 重启容器 docker restart gitlab 进入容器进行验证 docker exec

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5150 题目大意:给一幅N个点M条边的无向图,有一些边,其中一部分只能涂红色,一部分只能涂黑色,一部分两种颜色都可以涂.现要求红色的边不超过K条的生成树个数模1e9+7的值. 思路:感谢昂神滋磁,贴链接:http://sd-invol

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5155 There are N guests checking in at the front desk of the hotel. 2K (0 ≤ 2K ≤ N) of them are twins.There are M room

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5153 In an infinite chess board, some pawns are placed on some cells.You have a rectangular bomb that is W width and H

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5159 In normal football games, the winner team gets 3 points, loser team gets 0 point, and if there is a drawgame, bot

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5151You have a rectangle of size N × M, N rows from top to bottom and M columns from left to right,that is divided int

Long long ago there is a strong tribe living on the earth. They always have wars and eonquer others.One day, there is another tribe become their target. The strong tribe has decide to terminate them!!!There are m villages in the other tribe. Each vil

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5160 There is a tree with N nodes, and every node has a weighted value. A RIP (restricted increasing path)is a directe

w 同样的代码,不一样的php ENV.

传送门 B. Light bulbs 题意: 起初\(n\)个位置状态为\(0\),\(m\)次操作,每次操作更换区间状态:\(0\)到\(1\),\(1\)到\(0\). 共有\(T,T\leq 1000\)组数据,\(n\leq 10^6,m\leq 1000\). 最后输出状态为\(1\)的个数和. 思路: 一开始冲了一发维护差分,最后求出前缀和,成功\(TLE\). 其实只要发现有用的点只有\(2m\)个,之后从左到右扫一遍,类似于扫描线的思想,累加贡献就行了. Code #includ

[传送门] FFT第三题! 其实就是要求有多少三元组满足两短边之和大于等于第三边. 考虑容斥,就是枚举最长边,另外两个数组里有多少对边之和比它小,然后就是 $n^3$ 减去这个答案. 当 $n \leq 1000$ 时,直接暴力,因为如果继续 FFT 的话复杂度是 $O(slogs)$,$s$ 表示值域,值域都到 $10^5$,$100$ 组吃不消. 比 $1000$ 大就 FFT 做即可. #include <bits/stdc++.h> struct Complex { double r,