一.三道考题 开讲之前,我先请你做三道题目.(嘿嘿,得先把你的头脑搞昏才行--唉呀,谁扔我鸡蛋?)考题一,程序代码如下:void Exchg1(int x, int y){ int tmp; tmp = x; x = y; y = tmp; printf("x = %d, y = %d\n", x, y);}main(){ int a = 4,b = 6; Exchg1(a, b); printf("a = %d, b = %d\n"
通过typedef可以简单实现.也可以直接写. 写了两个简单的矩阵操作的函数简单示例. #include <stdio.h> #include <stdlib.h> const int ROW = 3; const int COL = 4; typedef int (* mat_pointer)[COL]; mat_pointer init_mat(mat_pointer a) { for (int i = 0; i < ROW; ++i) for (int j = 0; j
1. 用数组元素作函数实参 #include <iostream> using namespace std; int max_value(int x, int max) { return max > x ? max : x; } int main() { , y = ; ,,,},{,,,},{,,,}}; ][], i, j, ix, iy; ; i < x; i ++) { ; j < y; j++) { max = max_value(a[i][j],max); if(