Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
一.代码及注释 class Solution { public: int lengthOfLongestSubstring(string s) { int n = s.size(); //字符串的长度 ; //最长无重复子串的长度 //建立map表 key为字符 val为该字符的下一个坐标位置 //val取符号坐标+1用于更新start unordered_map<char,int> m; //定义start和end end即为当前字符,不断+1 ,end=;end<n;end++){
Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst
题目: Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of
Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana
最长无重复字符的子串 Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output
题目 最长无重复字符的子串给定一个字符串,请找出其中无重复字符的最长子字符串. 例如,在"abcabcbb"中,其无重复字符的最长子字符串是"abc",其长度为 3. 对于,"bbbbb",其无重复字符的最长子字符串为"b",长度为1. 解题 利用HashMap,map中不存在就一直加入,存在的时候,找到相同字符的位置,情况map,更改下标 public class Solution { /** * @param s: a s
功能:找出来一个字符串中最长不重复子串 def find_longest_no_repeat_substr(one_str): #定义一个列表用于存储非重复字符子串 res_list=[] #获得字符串长度 length=len(one_str) for i in range(length): tmp=one_str[i] for j in range(i+1, length): #用取到的字符与tmp中的字符相匹配,匹配不成功tmp字符继续增加,匹配成功直接跳出循环加入到res_list列表中
题目链接 Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2668 Daydream Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1658 Accepted Submission(s): 490 Problem Description Welcome to 2009 HDU Girl’s C
3. Longest Substring Without Repeating Characters 题面 Given a string, find the length of the longest substring without repeating characters. 给定字符串,找到最长无重复字串的长度 样例 Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc",
