javascript 写一段代码,判断一个字符串中出现次数最多的字符串,并统计出现的次数 function test(){ var bt = document.getElementById("bt"); bt.addEventListener("click",function(){ var str = "dafdsjkfnaiesdaadsllllllkkkkk444444444444444"; var obj = []; // 存放结果集的数组
python中判断某一个元素是否在一个列表中,可以使用关键字in 和 not in. 示例如下: 如果需要输出相应的信息,可以搭配使用if语句,这里不赘述. ------------------------------------------------------------------------------------------分割线------------------------------------------------------------------------------
感谢原作者,原理请看原作者的文章 http://www.html-js.com/article/1517 C#实现 public string rayCasting(PointF p, PointF[] poly) { var px = p.X; var py = p.Y; var flag = false; int l = poly.Length; ; ; i < l; i++) { var sx = poly[i].X; var sy = poly[i].Y; var tx = poly[j
1.在高德地图上绘制的多边形:经纬度逗号分隔格式:上面是用来方便存坐标的对象:下面是方法测试:直接复制代码即可运行 public class Point { private Double x; private Double y; public Point (Double x , Double y) { this.x = x; this.y = y; } public Double getX() { return x; } public void setX(Double x) { this.x =
declare @ip1 varchar(20)declare @ip2 varchar(20)set @ip1='221.231.138.101'set @ip2='255.255.255.255' select count(1) from vhhostlist where (cast(dbo.split(s_serverip,'.',0) as bigint)*(256*256*256)+cast(dbo.split(s_serverip,'.',1) as bigint)*(256*256
/*函数的输入:(1)当前点的坐标p(2)区域顶点数组pt[]:(3)顶点数nCount 输出: 在区域内返回TRUE,否则返回FALSE. Point类型是一个结构: struct Point { 类型 x;//此处类型根据采用的经纬度类型决定. 类型 y; };*/BOOL PtInPolygon(Point p, Point pt[], int nCount){ int nCross = 0; for (int i = 0; i < nCount; i++) {
https://msdn.microsoft.com/en-us/library/windows/desktop/ms533826(v=vs.85).aspx The purpose of hit testing is to determine whether the cursor is over a given object, such as an icon or a button. The following example creates a plus-shaped region by f