using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace StateMachine { class Program { static void Main(string[] args) { //输出十进制 - 二进制的值 Console.WriteLine(State.A + ))); Console.Wr
A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 100000/100000 K (Java/Others) Total Submission(s): 1905 Accepted Submission(s): 668 Problem Description Corrupt governors always find ways to get dirty money
Given you n sets.All positive integers in sets are not less than 1 and not greater than m.If use these sets to combinate the new set,how many different new set you can get.The given sets can not be broken. 代码: #include<bits/stdc++.h> using namespace
忘记在哪里看到一个面试题:把int a,b的值互换,不能使用临时变量.刚开始完全懵逼,脑子里面全是浆糊,不知道如何下手.查看答案后猛地一惊,心想居然还有这种操作,真是叹为观止,真的感觉自己的基础是如此的薄弱.我们一直在追逐着各种狂拽,酷炫,吊炸天的框架,技术,以及各种库,并且乐此不疲总以为学到这些技术就有去吹牛的资本,就可以拿到高工资.其实可能,很有可能你连最基本一些编程知识都没掌握好.当然我也是其中一个,这次就系统学习下基本编程中的按位运算!下面是上面面试题的答案: public void s
Count Color Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 38921 Accepted: 11696 Description Chosen Problem Solving and Program design as an optional course, you are required to solve all kinds of problems. Here, we get a new problem.
一.位运算实例 1.用一个表达式,判断一个数X是否是2的N次方(2,4,8,16.....),不可用循环语句. X:2,4,8,16转化成二进制是10,100,1000,10000.如果减1则变成01,011,0111,01111.两者做按位与运算,结果如果为0,则X是2的N次方. 2.统计一个整数的二进制中1的个数 int count_number_of_one(int number) { int counter = 0; while (number) { counter++; number