//解除绑定蓝牙 //http://www.520m.com.cn/api/pet/remove-binding?healthy_id=72&pet_id=100477&access-token=YWdqPCWdt3_IqkrTK-U5vS458ZWfcdeT public function actionRemoveBinding(){ $healthy_id = Yii::$app->request->get('healthy_id'); if(empty($healthy_
Contains Duplicate II Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. Have you met this question in a
一.位运算实例 1.用一个表达式,判断一个数X是否是2的N次方(2,4,8,16.....),不可用循环语句. X:2,4,8,16转化成二进制是10,100,1000,10000.如果减1则变成01,011,0111,01111.两者做按位与运算,结果如果为0,则X是2的N次方. 2.统计一个整数的二进制中1的个数 int count_number_of_one(int number) { int counter = 0; while (number) { counter++; number
Reduced ID Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 9310 Accepted: 3740 Description T. Chur teaches various groups of students at university U. Every U-student has a unique Student Identification Number (SIN). A SIN s is
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 这里题目要求找出出现次数超过n/2的元素. 可以先排序,