Shuffle a set of numbers without duplicates. Example: // Init an array with set 1, 2, and 3. int[] nums = {1,2,3}; Solution solution = new Solution(nums); // Shuffle the array [1,2,3] and return its result. Any permutation of [1,2,3] must equally lik
random模块是产生随机数的模块 1.random.random() 这是产生0~1之间一个随机浮点数,但是不会包括1 import random num = 0 while num < 10: print(random.random(),'\t',end='') num += 1 if num % 5 == 0: print() 0.5498432689828007 0.3831223570880221 0.9274241638226295 0.8374157068420778 0.1752
建议75:集合中的元素必须做到compareTo和equals同步 实现了Comparable接口的元素就可以排序,compareTo方法是Comparable接口要求必须实现的,它与equals方法有关系吗?有关系,在compareTo的返回为0时,它表示的是 进行比较的两个元素时相等的.equals是不是也应该对此作出相应的动作呢?我们看如下代码: class City implements Comparable<City> { private String code; private S