The problem here is that you've defined an anonymous method which returns a string but are trying to assign it directly to a string. It's an expression which when invoked produces a string it's not directly a string. It needs to be assigned to a comp
建议32: 静态变量一定要先声明后赋值 这标题看着让人很纳闷,什么叫做变量一定要先声明后赋值?Java中的变量不都是先声明后使用的吗?难道还能先使用后声明?能不能暂且不说,我们先来看一个例子,代码如下: public class Client { public static int i=1; static{ i=100; } public static void main(String[] args) { System.out.println(i); } } 这段程序很简单,输出100嘛!对,确
2012-03-25 12:12 a786013819 | 分类:数据库DB | 浏览1393次 $sql = "select field1 from pre_common_member_profile where uid='$username'";得到的结果是这样的:field11234怎么把1234赋值给变量 你是只取这一个值还是要取数组.只取一个的话.$sql = "select field1 from pre_common_member_profile where u
添加BeanShell PostProcessor来获取,具体代码如下: import com.jayway.jsonpath.JsonPath; import com.jayway.jsonpath.Predicate; import net.minidev.json.JSONArray; public class Test { public static String readjson(String json, String jsonPath) { try { Object value =