S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ
自定义排序需要单独写一个compare函数 例1 LeetCode 056. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an interval. * struct Interval { *
mysql如何用order by 自定义排序 id name roleId aaa bbb ccc ddd eee ,MySQL可以通过field()函数自定义排序,格式:field(value,str1,str2,str3,str4),value与str1.str2.str3.str4比较,返回1...,如遇到null或者不在列表中的数据则返回0. 例如:,,,,); 结果: id name roleId bbb ccc ddd aaa eee ,locate(substr,str)函数返回子
使用STL库sort函数对vector进行排序,vector的内容为对象的指针,而不是对象. 代码如下 #include <stdio.h> #include <vector> #include <algorithm> using namespace std; class Elm { public: int m_iSortProof; private: int __m_iValue; static int __m_iCnt; public: Elm(); int get