Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and
项目中用到了Android Fragment 在程序异常的时候 fragment 点击会造成fragment 重叠 在fragmentActivity中加入一下方法 @Override public void onSaveInstanceState(Bundle outState) {//防止重叠 // TODO Auto-generated method stub //super.onSaveInstanceState(outState); }
可重叠的k次最长重复子串 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 21003; int t1[N], t2[N], c[N]; void st(int *x, int *y, int *sa, int n, int m) { int i; for(i = 0; i < m; ++i) c[i] = 0; for(i = 0;
Musical Theme Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 25348 Accepted: 8546 Description A musical melody is represented as a sequence of N (1<=N<=20000)notes that are integers in the range 1..88, each representing a key on the