转载地址:http://m.blog.csdn.net/blog/u010489766/9229011 题目链接:http://poj.org/problem?id=1276 题意:机器里面共有n种面额的钱币,每种各ni张,求机器吐出小于等于所要求钱币的最大值 解析1:这题大牛都用了多重背包,不过,我一同学想出了一种就这题而言特别简单有效的方 法.(话说我就认为这题本来就不需要用到背包的,因为n的范围只到10,太小了).方法就是对钱进行遍历,看这些钱一共能组成多少面额的钱,然后从 cash向下枚

Cash Machine Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 26172   Accepted: 9238 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The ma

Cash Machine Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 33444   Accepted: 12106 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The m

Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 24213 Accepted: 8476 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machin

<span style="color:#000099;">/* Cash Machine Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 26604 Accepted: 9397 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bi

个人心得:多重背包,自己根据转换方程写总是TLE,后面去网上看了二进制转换,不太理解: 后面仔细想了下,用自己的思想理解下把,就是将对应number,cash总和用二进制拆分, 然后全部装入到一个数组,这样子就可以减少循环,同时转变为01背包,这样子想把, 5 5,就变成了5,10,20,5然后用01背包互相取与不取也可以组成对应的k=1-5乘以5的值. 转换方式如下: ) { t[account++]=k*cash[i]; number[i]-=k; k=k*; } t[account++]=

Cash Machine Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 38986   Accepted: 14186 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The m

Cash Machine Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 30006   Accepted: 10811 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The m

题目地址:http://poj.org/problem?id=1276 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N distinct bill denominations, say Dk, k=1

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24067   Accepted: 8414 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses ex

Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N distinct bill denominations, say Dk, k=1,N, and for each denomination Dk the

Problem Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N distinct bill denominations, say Dk, k=1,N, and for each denominatio

Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N distinct bill denominations, say Dk, k=1,N, and for each denomination Dk the

Time Limit: 1000MS   Memory Limit: 10000KB   64bit IO Format: %lld & %llu Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses exactly N di

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 35387   Accepted: 12816 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses e

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 44409   Accepted: 16184 Description A Bank plans to install a machine for cash withdrawal. The machine is able to deliver appropriate @ bills for a requested cash amount. The machine uses e

题意: 有n种纸币,已知每种纸币的面值和数量,求所能凑成的不超过cash的最大总面值. 分析: 这道题自己写了一下TLE了,好可耻.. 找了份比较简洁的代码抄过来了..poj1276 #include <cstdio> #include <cstring> ; + ; bool vis[maxp];//是否到达总面值i int used[maxp];//到达总面值i时,该种纸币所用的数量 int a[maxn], b[maxn];//每种纸币的数量以及面值 int cash, n;

题目大意 给定一个容量为M的背包以及n种物品,每种物品有一个体积和数量,要求你用这些物品尽量的装满背包 题解 就是多重背包~~~~用二进制优化了一下,就是把每种物品的数量cnt拆成由几个数组成,1,2,4,~~~cnt-2^K+1,k满足cnt-2^K+1>0的最大整数,体积和价值乘上相应的数就是相应物品的价值和体积,这样用这些物品能够表示1~~cnt所有的情况~~~这就转化成01背包了~~~ 代码: #include <iostream> #include <cstdio>

http://poj.org/problem?id=1276 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #define For(n) for(int i=1; i<=(n); i++) #define maxn 100010 using namespace std; int dp[maxn]; struct node { int n; int m; }p

最近的很多题解应该都是dp相关的了,emmm因为dp对我而言思考难度比较大,那么为了理顺自己的思路当然只能通过写blog整理了.愿我能成功搞定dp这个大关!(至少中等难度的dp要能够解决啊o(TヘTo)) 题意与分析 这条题目是一条明显的多重背包题目.遇到这种题目,我们首先简单的转化为01背包问题来解决.(思路:把$n_i$个$v_i$拆分开来)但是呢,有一个二进制优化可以采用,就是在这个拆分机制上.重点就是这段代码: while(num-k>=0) { things[cnt++]=d*k; n