--使用CAST将varchar转换成int类型排序 select distinct(zone_id) from guild_rank_info order by CAST(zone_id as SIGNED); --使用CONVERT将varchar转换成int类型排序 select distinct(zone_id) from guild_rank_info order by convert(zone_id , SIGNED); null
參考文档: How to Convert a Long to Varchar2 (文档 ID 228532.1) /*long类型字段转换成varchar2类型*/ --建表 create table dxmy_long(lon long,var varchar2(100 )); --插数 insert into dxmy_long values( '丹心','明月' ); commit; --查看 declare v1 varchar2(100 ); begin select lon into
List<Object> list = getList(); return (List<Customer>) list; Compiler says: cannot cast List<Object> to List<Customer> 不能将Object集合强制转换成实体集合! you can always cast any object to any type by up-casting it to Object first. in your cas
这是替代方法 先使用着 select * from ofgroup where groupId in (select groupId from ofgroup where uid ='".$_GET['value']."' and useraid='0') groupid定位死 就显示一个 与它对应的也是相同的 每个人的清况不一样 sql语句也大有区别
利用拼接字符串转换point select GeomFromText(CONCAT('POINT(',lng,' ',lat,')')) from community limit 1; 插入字段到新表 create table communityN as select *,GeomFromText(CONCAT('POINT(',lng,' ',lat,')')) location from community;
今天在写代码的时候遇到了点问题,特意记下,以免忘记!四舍五入方法: // num为传入的值,n为保留的小数位 function fomatFloat(num,n){ var f = parseFloat(num); if(isNaN(f)){ return false; } f = Math.round(num*Math.pow(10, n))/Math.pow(10, n); // n 幂 var s = f.toString(); var rs = s.indexOf('.'); //判定如
