题目链接 F. Bear and Fair Set time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a grizzly bear. He is big and dreadful. You were chilling in the forest when you suddenly met him. It's v

http://poj.org/problem?id=1459 嗯,网络流模板...多源点多汇点的图,超级汇点连发电厂,用户连接超级汇点 Status Accepted Time 391ms Memory 1588kB Length 2166 Lang G++ Submitted 2018-05-23 14:43:22 Shared RemoteRunId 18625420 #include <iostream> #include <string.h> #include <cm

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 63339   Accepted: 24434 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by

身边的小伙伴们都在愉快地刷网络流,我也来写一发模板好了. Network Flow - Maximum Flow Time Limit : 1 sec, Memory Limit : 65536 KB Japanese version is here Maximum Flow A flow network is a directed graph which has a  and a . In a flow network, each edge has a capacity . Each edge

题目: 题目描述 有 n(0<n<=1000)个点,m(0<m<=1000)条边,每条边有个流量 h(0<=h<35000),求从点 start 到点 end 的最大流. 输入格式 第一行:4 个整数,分别是 n,m,start,end .接下来有 m 行,每行四个三个整数 a,b,h,分别表示 a 到 b,流量为 h 的一条边. 输出格式 输出从点 start 到点 end 的最大流. 样例数据 1 输入 [复制]   7 14 1 7 1 2 5 1 3 6 1 4

题意:1是源点,m是汇点,求出来最大流量,没什么好说的就是练习最大流的模板题 ************************************************************** 先用Edmonds-Karp的算法做一下试试吧重边贡献了 1W,要加上所有的重边才算是两点间最大流量 *************************************************************************************************

Problem Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes are opened for passengers

链接: http://poj.org/problem?id=1087 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82835#problem/C http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88230#problem/J(密码:0817) n个插座,m个电器及其对应的插座,k个转化器,前一个插座可以转化为后一个插座,问最少有多少设备没有插座用,转换器数量不限最大流,源点

题目大意:就是由于下大雨的时候约翰的农场就会被雨水给淹没,无奈下约翰不得不修建水沟,而且是网络水沟,并且聪明的约翰还控制了水的流速, 本题就是让你求出最大流速,无疑要运用到求最大流了.题中m为水沟数,n为水沟的顶点,接下来Si,Ei,Ci分别是水沟的起点,终点以及其容量.求源点1到终点m的最大流速. EK算法详解参考链接 EK模板 #include<iostream> #include<queue> #include<cstring> #include<algor

#101. 最大流 内存限制:512 MiB时间限制:5000 ms标准输入输出 题目类型:传统评测方式:文本比较 上传者: 匿名 提交提交记录统计讨论测试数据   题目描述 这是一道模板题. 给定 n nn 个点,m mm 条边,给定每条边的容量,求从点 s ss 到点 t tt 的最大流. 输入格式 第一行四个整数 n nn.m mm.s ss.t tt.接下来的 m mm 行,每行三个整数 u uu.v vv.c cc,表示 u uu 到 v vv,流量为 c cc 的一条边. 输出格式

http://acm.hdu.edu.cn/showproblem.php?pid=1532 Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13790    Accepted Submission(s): 6527 Problem Description Every time it rains on F

模板题:POJ1273 EK: #include <queue> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int n,m,jy,map[305][305],c[305][305],a[305],p[305]; bool vis[305]; int M(int e) { int f=0; queue<int>q; while(1){

src:源点 sink:汇点 #include<queue> #include<iostream> #include<string.h> #include<stdio.h> using namespace std; ; , maxm = ; struct Edge{ int v, f, nxt; }; int src, sink; ]; int nume; Edge e[maxm*+]; void addedge(int u, int v, int c){

Drainage DitchesHal Burch Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time to regrow. Thus, Farmer John has built a se

Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time to regrow. Thus, Farmer John has built a set of drainage

链接: http://poj.org/problem?id=1273 代码: //Dinic #include<stdio.h> #include<string.h> #include<queue> #include<algorithm> using namespace std; ; ; struct Edge { int v, flow, next; }edge[MAXN]; int Head[MAXN], cnt; int Layer[MAXN]; vo

链接: http://poj.org/problem?id=1273 Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 63763   Accepted: 24613 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This m

网络流模板题. ========================================================================================================== #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cmath> #include<queue>

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 78671   Accepted: 30687 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by

[BZOJ1001]狼抓兔子(网络流) 题面 Description 现在小朋友们最喜欢的"喜羊羊与灰太狼",话说灰太狼抓羊不到,但抓兔子还是比较在行的, 而且现在的兔子还比较笨,它们只有两个窝,现在你做为狼王,面对下面这样一个网格的地形: 左上角点为(1,1),右下角点为(N,M)(上图中N=4,M=5).有以下三种类型的道路 1:(x,y)<==>(x+1,y) 2:(x,y)<==>(x,y+1) 3:(x,y)<==>(x+1,y+1) 道路

[BZOJ3931][CQOI2015]网络吞吐量(最短路,网络流) 题面 跑到BZOJ上去看把 题解 网络流模板题??? SPFA跑出最短路,重新建边后 直接Dinic就行了 大火题嗷... #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath> #include<algorithm> #include<se