package com.swift; public class Switch_Test { public static void main(String[] args) { /* * switch语句能否作用在byte上,能否作用在long上,能否作用在String上? */ byte zijie = 3; System.out.println(zijie); long changzheng=3; switch (changzheng) { //cannot switch on a value
先看下面几个sql语句 1 SET QUOTED_IDENTIFIER ON 2 SELECT * FROM "USER" WHERE a='netasp' 3 4 SET QUOTED_IDENTIFIER ON 5 SELECT * FROM [USER] WHERE a='netasp' 6 7 SET QUOTED_IDENTIFIER OFF 8 SELECT * FROM [USER] WHERE a="netasp" 9 10
SET QUOTED_IDENTIFIER ON SELECT * FROM "USER" WHERE a='netasp' SET QUOTED_IDENTIFIER ON SELECT * FROM [USER] WHERE a='netasp' SET QUOTED_IDENTIFIER OFF SELECT * FROM [USER] WHERE a="netasp" SET QUOTED_IDENTIFIER OFF SELECT * FROM [USER
笔者在自学Python的过程中,对于if __name__='__main__'的用法感到很困惑,在think Python一书中原作者的源代码是这么解释if __name__='__main__'语句的: # the following condition checks whether we are # running as a script, in which case run the test code, # or being imported, in which case don't.
出错代码段: switch (t) { case 0: int a = 0; break; default: break; }编译时提示:“error C2361: initialization of 'a' is skipped by 'default' label”.这怎么可能? C++约定,在块语句中,对象的作用域从对象的声明语句开始直到块语句的结束,也就是说default标号后的语句是可以使用对象a的.如果程序执行时从switch处跳到default处,就会导致对象a没有被正确地初