不啰嗦,直接上图,大概实现效果如下: 有上面这样一份数据,将他们按照userAccount和submitTime进行分组,然后提前每组数据的前两条记录 提取后数据如下: 实现的SQL如下: select t.* from (select *,row_number() over(partition by userAccount, submitTime order by submitTime) rn from demoTable) t @_@! 结束啦~~
一.条件字段为数值的情况 select * from tb where id=@id; --当前记录 select top 1 * from tb where id>@id order by id; --下一条记录 select top 1 * from tb where id<@id order by id desc --上一条记录 二.以排序的思路出发的一种方案 ;WITH TUsers AS ( SELECT *, ROW_NUMBER() OVER (
用到的是这个函数: group_concat() select group_buying_id, group_concat(app_user_ids) from org_user_group group by group_buying_id 输出的结果: select group_buying_id, group_concat(app_user_ids) from org_user_group where group_buying_id=10 这是查询一条
方法一: 使用TOP SELECT TOP 1 * FROM user; SELECT TOP 1 * FROM user order by id desc; 方法二: 使用LIMIT SELECT * FROM user LIMIT 1; SELECT * FROM user ORDER BY id ASC LIMIT 1; SELECT * FROM user ORDER BY id DESC LIMIT 1; --------------------- 原文:https://blog.cs
方法一: 使用TOP SELECT TOP 1 * FROM user; SELECT TOP 1 * FROM user order by id desc; 方法二: 使用LIMIT SELECT * FROM user LIMIT 1; SELECT * FROM user ORDER BY id ASC LIMIT 1; SELECT * FROM user ORDER BY id DESC LIMIT 1; 转载至:https://www.cnblogs.com/weimingxin/p
首先描述问题,student表中有字段startID,endID.garde表中的ID需要对应student表中的startID或者student表中的endID才能查出grade表中的name字段,这时候问题就来了,如果需要一条sql一句同时查出garde表中的两条数据怎么办?(两表的关联字段为 SID) sql="select b.name,c.name as name2 from student a,garde b,grade c where a.SID=b.SID and a.SID=c