在 强化学习实战 | 表格型Q-Learning玩井字棋(一)中,我们构建了以Game() 和 Agent() 类为基础的框架,本篇我们要让agent不断对弈,维护Q表格,提升棋力.那么我们先来盘算一下这几个问题: Q1:作为陪练的一方,策略上有什么要求吗? A1:有,出棋所导致的状态要完全覆盖所有可能状态.满足此条件下,陪练的棋力越强(等同于环境越严苛),agent训练的效果越好.AlphaGo的例子告诉我们,陪练的策略也是可以分阶段调整的:前期先用人类落子的预测模型当陪练,中后期让agent

Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends has decided to exchange gifts of money. Each of these friends might or might not give some money to any or all of the other friends. Likewise, each friend might or might not receiv

http://acm.hdu.edu.cn/showproblem.php?pid=4976 2014 Multi-University Training Contest 10 1006 A simple greedy problem. Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 20    Accepted Submission(s

Greedy Mouse 时间限制:1000 ms  |  内存限制:65535 KB 难度:3   描述 A fat mouse prepared M pounds of cat food,ready to trade with the cats guarding the warehouse containing his favorite food:peanut. The warehouse has N rooms.The ith room containsW[i] pounds of pea

huffman coding, greedy algorithm. std::priority_queue, std::partition, when i use the three commented lines, excution time increase to 15ms from 0ms, due to worse locality? thanks to http://acm.hdu.edu.cn/discuss/problem/post/reply.php?action=support

在现实世界中,有这样一类问题:它有n个输入,而它的解就由这n个输入的某个子集组成,不过这个子集必须满足某些事先给定的条件.把那些必须满足的条件称为约束条件:而把满足约束条件的子集称为该问题的可行解.问题的简单描述:In={n个输入}: 显然,满足约束条件的子Ina是In的子集: 集可能不止一个,一般来说Ina满足约定的条件: 可行解不是唯一的.Ina构成问题的解. 贪心方法是一种改进了的分级处理方法,选择能产生问题最优解的最优量度标准是使用贪心法设计求解的核心问题.但是,要选出最优量度标准并不是

作者:supernova 出处:http://community.topcoder.com/tc?module=Static&d1=tutorials&d2=greedyAlg John Smith is in trouble! He is a TopCoder member and once he learned to master the "Force" of dynamic programming, he began solving problem after p

题目地址:http://ac.jobdu.com/problem.php?pid=1453 题目描述: Tino wrote a long long story. BUT! in Chinese... So I have to tell you the problem directly and discard his long long story. That is tino want to carry some oranges with "Carrying pole", and he

I - 秋实大哥下棋 Time Limit: 3000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status 胜负胸中料已明,又从堂上出奇兵.秋实大哥是一个下棋好手,独孤求败的他觉得下棋已经无法满足他了,他开始研究一种新的玩法. 在一个n×m的棋盘上,放置了k个车,并且他在棋盘上标出了q个矩形,表示矩形内部是战略要地. 秋实大哥要求一个矩形内的每一个格子,都至少能被一辆在矩形内的车攻击到,

 Greedy Gift Givers  The Problem This problem involves determining, for a group of gift-giving friends, how much more each person gives than they receive (and vice versa for those that view gift-giving with cynicism). In this problem each person sets

两次SPFA 第一关找:从1没有出发点到另一个点的多少是留给油箱 把边反过来再找一遍:重每一个点到终点最少须要多少油 Greedy Driver Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward is a truck driver of a big company. His daily work is driving a truck from one city to another. Recently he got a long d

Greedy Change time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Billy investigates the question of applying greedy algorithm to different spheres of life. At the moment he is studying the ap

Greedy Gift Givers 贪婪的送礼者 对于一群(NP个)要互送礼物的朋友,GY要确定每个人送出的钱比收到的多多少. 在这一个问题中,每个人都准备了一些钱来送礼物,而这些钱将会被平均分给那些将收到他的礼物的人. 然而,在任何一群朋友中,有些人将送出较多的礼物(可能是因为有较多的朋友),有些人有准备了较多的钱. 给出一群朋友,没有人的名字会长于 14 字符,给出每个人将花在送礼上的钱,和将收到他的礼物的人的列表, 请确定每个人收到的比送出的钱多的数目. PROGRAM NAME: gi

Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends hasdecided to exchange gifts of money. Each of these friends might ormight not give some money to any or all of the other friends.Likewise, each friend might or might not receive m

greedy算法的核心思想是首先计算覆盖面大的部分,然后依次寻找其他覆盖面最大的部分.该算法的使用场景就像他的名字一样,当符合贪婪属性的时候就可以考虑. states_needed = set(['北京', '上海', '广州', '深圳', '杭州', '南京', '石家庄', '银川']) stations = {} stations['kone'] = set(['北京', '上海', '广州']) stations['ktwo'] = set(['北京''杭州', '南京']) stat

[CF1132G]Greedy Subsequences 题目大意: 定义一个序列的最长贪心严格上升子序列为:任意选择第一个元素后,每次选择右侧第一个大于它的元素,直到不能选为止. 给定一个长度为\(n(n\le10^6)\)的序列\(A\),同时给定一个常数\(k\),求该序列的所有长度为\(k\)的子区间的最长贪心严格上升子序列的长度. 思路: 不难发现,若将每个点和右侧第一个大于它的元素相连,可以得到一个森林,其中每个结点对应的父结点为序列中右侧第一个大于它的元素.若没有区间长度为\(k\

[CF1132G]Greedy Subsequences(线段树) 题面 CF 题解 首先发现选完一个数之后选择下一个数一定是确定的. 对于每个数预处理出左侧第一个比他大的数\(L\),那么这个数加入进来之后\([L+1,i]\)的答案都会增加一,拿线段树维护一下就行了. #include<iostream> #include<cstdio> using namespace std; #define MAX 1000100 inline int read() { int x=0;b

贪心搜索(greedy search) 贪心搜索最为简单,直接选择每个输出的最大概率,直到出现终结符或最大句子长度. 集束搜索(beam search) 集束搜索可以认为是维特比算法的贪心形式,在维特比所有中由于利用动态规划导致当字典较大时效率低,而集束搜索使用beam size参数来限制在每一步保留下来的可能性词的数量.集束搜索是在测试阶段为了获得更好准确性而采取的一种策略,在训练阶段无需使用. 假设字典为[a,b,c],beam size选择2,则如下图有: 1:在生成第1个词的时候,选择概

Greedy Gift Givers A group of NP (2 ≤ NP ≤ 10) uniquely named friends has decided to exchange gifts of money. Each of these friends might or might not give some money to any or all of the other friends. Likewise, each friend might or might not receiv

present a file by binary character code,let the less characters can be presented simplier. package greedy; import java.util.Iterator; import java.util.LinkedList; public class huffman { private static class Node{ private Node left ; private Node righ

many activities will use the same place, every activity ai has its'  start time si and finish time fi.let the number of activities to be as many as possible. 1. dynamic programming use ak be a knife to cut the set activities into two parts and recurs