/* 树状数组第三种模板(改段求段)不解释! 不明白的点这里:here! */ #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #define N 100005 using namespace std; typedef long long LL; LL ss[N], B[N], C[N]; int n, m; void addB(int x, int k){/
题目描述 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The
题目链接:点击打开链接 题意:给定n*m的二维平面 w个操作 int mp[n][m] = { 0 }; 1.0 (x1,y1) (x2,y2) value for i : x1 to x2 for j : y1 to y2 mp[i][j] += value; 2.1 (x1, y1) (x2 y2) ans1 = 纵坐标在 y1,y2间的总数 ans2 = 横坐标不在x1,x2间的总数 puts(ans1-ans2); more format: for i : 1 to n for j :
SELECT CONVERT(VARCHAR(10), dtCreateTime, 120) AS dtStatisticsCreateDate, COUNT(1) AS nStatisticsCount FROM Web_Statistics WHERE datepart(hh,dtCreateTime)>=10 AND datepart(hh,dtCreateTime)<11
BSS段:BSS段(bss segment)通常是指用来存放程序中未初始化的全局变量的一块内存区域.BSS是英文Block Started by Symbol的简称.BSS段属于静态内存分配. 数据段:数据段(data segment)通常是指用来存放程序中已初始化的全局变量的一块内存区域.数据段属于静态内存分配. 代码段:代码段(code segment/text segment)通常是指用来存放程序执行代码的一块内存区域.这部分区域的大小在程序运行前就已经确定,并且内存区域通常属于只
Tic和toc函数可以计算运行一段时间的代码. 例如: clc tic d=zeros(1,10000); for i=1:10000 d(i)=i; end toc tic c=1; for i=1:10000 c=[c:i]; end toc 运行结果如下: Elapsed time is 0.000158 seconds. Elapsed time is 0.152307 seconds. 只要用tic和toc函数,不需要自己计算前后时间的差,tic函数会记录起始时刻,toc函数会自动计算