element ui是一个非常不错的vue的UI框架,element对table进行了封装,简化了vue对表格的渲染. element ui表格中有一个功能是展开行,在2.0版本官网例子中,只可以点击右箭头可以展开,我们的很多需求是点击某一行展开 那是不是无法实现呢?其实,借助element ui的一些属性,轻松实现点击某行展开,我们还是用2.0.9版本官网的例子, 对齐改造,使之可以做到这点 <template> <el-table :data="tableData5&quo
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No
Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Follow up: What if the BST is modified (insert/delete operations) often and you nee
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For exampl
$('#searchBtn').on('click',function(){ var type = $(this).data('type'); active[type] ? active[type].call(this) : ''; }); // 点击获取数据 var active = { getInfo: function () { var fileName=$('#fileName').val(); // var startTime=$('#startTime').val(); // var
Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Hide Tags Depth-first Search Linked List 这题是将链表变成二叉树,比较麻烦的遍历过程,因为链表的限制,所以深度搜索的顺序恰巧是链表的顺序,通过设置好递归函数的参数,可以在深度搜索时候便可以遍历了. TreeNode * he