来源:https://segmentfault.com/a/1190000014827485 element UI的Cascader级联选择器编辑时 vue.js element-ui 2 element UI的Cascader级联选择器组件在编辑时,它需要一个数组值,而一般我们api给的数据是一个值.两个解决方法: 说服后台,让后台给arr. 自己动手丰衣足食,根据给定的值获取级联关系数组. 刚好这两天解决了这个问题. 写了一个方法如下: function getTreeDeepArr(key
如有雷同,不胜荣幸,若转载,请注明 C#中自定义类数组和结构数组的使用 最近在很多项目中发现很多时候给定的数组要实现某个逻辑或处理很是麻烦,一维数组,二维数组,,,等等需要经过n多转换,还不如自己写一个自定义数组,既方便又节省时间,以下是类数组,其实相当于定义了一个实体类一样,只是使用的时候写成数组的形式在用 Class RGB { public byte red; public byte green; public byte blue; public RGB(byte r,byte g,byt
［抄题］: You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. The Next Greater Number of a number x in nums
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, 1 ≤ k ≤ array'
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. Example 1: Input: [3,2,1,5,6,4] and k = 2 Output: 5 Example 2: Input: [3,2,3,1,2,4,5,5,6] and k = 4 Output:
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. Example 1: Input: [3,2,1,5,6,4] and k = 2 Output: 5 Example 2: Input: [3,2,3,1,2,4,5,5,6] and k = 4 Output:
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. class Solution { public: //O(n) Space compexity vector<int> majorityElement01(vector<int>&
class MyArray: '''保证输入的内容是整型.浮点型''' def ___isNumber(self, num): if not isinstance(num, (int,float)): return False return True #开始写构造函数,接受可变长度的数组 def __init__(self, *args): if args == None: self.__value = [] else: for a in args: if not self.___isNumbe
