FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13643    Accepted Submission(s): 6011Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster i

J. FatMouse's Speed FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14980    Accepted Submission(s): 6618 Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster

FatMouse's Speed Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1160 Description FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13133    Accepted Submission(s): 5778Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster i

FatMouse's Speed Time Limit: 2 Seconds      Memory Limit:65536 KB     Special Judge FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of thi

p的思路不一定要到最后去找到ans:也可以设置成在中间找到ans:比如J - FatMouse's Speed 这个题,如果要是让dp[n]成为最终答案的话,即到了i,最差的情况也是dp[i-1],就很难去保存路径,但是如果换一个思路,让dp[i]必须去参与,如果无法与前面的结合,那么就新开一个. 最后路径是保存的逆序的,那么开一个stack就可以解决. //显然这个题是要维护两个变量的最长上升子序列 #include <iostream> #include <fstream> #

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20803    Accepted Submission(s): 9227Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster

http://acm.hdu.edu.cn/showproblem.php?pid=1160 FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12338    Accepted Submission(s): 5405Special Judge Problem Description FatMouse be

FatMouse's Speed Time Limit: 2 Seconds      Memory Limit:65536 KB     Special Judge FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of thi

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7213    Accepted Submission(s): 3181Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster it

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1160 FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 17386    Accepted Submission(s): 7694Special Judge Problem Description

J - FatMouse's Speed DP的题写得多了慢慢也有了思路,虽然也还只是很简单的DP. 因为需要输出所有选择的老鼠,所以刚开始的时候想利用状态压缩来储存所选择的老鼠,后面才发现n太大1<<1000根本存不下来... 思路的话其实也不难,把体重排序之后,对速度求一个最长下降子序列即可. 对于每一次求最长有序子序列,只需要全部遍历一遍,遍历的时候,将该位置作为所选择序列的最后一个元素,DP[i]即为该序列的最大长度. 代码: // Created by CAD on 2019/10/

FatMouse's Speed Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 24573    Accepted Submission(s): 10896Special Judge Problem Description FatMouse believes that the fatter a mouse is, the faster

Problem Description FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre

FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are increasing, but the speed

Problem Description FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre

Problem Description FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre

      #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; #define met(a,b) (memset(a,b,sizeof(a))) #define N 1100 #define INF 0xffffff struct node { int w, s, nu

Problem Description FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are incre