Reincarnation Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 843 Accepted Submission(s): 283 Problem Description Now you are back,and have a task to do:Given you a string s consist of lower
// Example3.cpp : 定义控制台应用程序的入口点. //以特定单词为分界,求取字符串的左右子串 #include "StdAfx.h" #include <string> #include <iostream> using namespace std; int main(void) { string str,str1,str2; int index; str="cjc is a good boy"; cout<<&q
SPOJ Problem Set (classical) 694. Distinct Substrings Problem code: DISUBSTR Given a string, we need to find the total number of its distinct substrings. Input T- number of test cases. T<=20; Each test case consists of one string, whose length is <=
1.for循环 和while相比 l=[1,2,3] i=0 while i <len(l) print(l[i]) i+=1 l=['a','b','c'] for item in l: print(item) 字典中的应用: dic={'x':111,'y':222,'z':333} for k in dic: print(k,dic[k]) while循环称为条件循环,循环的次数取决于条件何时为false for称为迭代器循环,循环的次数取决于数据包含的元素的个数 2.for循环专门用来取
利用help_topic表把字符串转换成行(分隔符号',') ),) as `id` FROM mysql.`help_topic`; 统计字符串每个子串出现次数(分隔符号',') ),) AS `sub_column`,COUNT(A.`column`) AS `count` FROM `test` A ) ),);