Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = [
[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项 描述 Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
forEach()取出数组中2的倍数和3的倍数的数 //for IE if(!Array.prototype.forEach){ Array.prototype.forEach = function(callback, thisArg){ var T, k; if(this == null){ throw new TypeError(" this is null or not defined"); } var O = Object(this); var len = O.length &
刚学习程序,感觉写代码 很有意思,所以把自己的感悟写下来啦,第一次写博客,可能是菜鸟中的菜鸟 时间久了,相信就会写的很好哦! for和 foreach 的数组遍历 比较 很简单的程序,不解释啦! using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(